Energy, Year 10: energy stores, kinetic and gravitational energy:全部卡片
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- An object, or a group of objects, picked out so that its energy changes can be followed
A system
提示The solar ______ and the digestive ______ use the same word for a set of parts treated as one thing.
为什么Before any energy calculation you decide what is inside your boundary: the kettle and its water, say, or a ball and the Earth. When the chosen set of objects changes, the way its energy is stored changes too. AQA opens the Energy topic with this idea.
- A car brakes to a stop on a level road. Into which energy store does most of the car's kinetic energy go?
The thermal store of the brakes (and then the surroundings)
提示Think about what you would notice if you could touch the discs just after a hard stop.
为什么Friction between the pads and the discs does work on the car, emptying its kinetic store. The same amount of energy raises the temperature of the brakes, which then warm the air around them. A vehicle slowing down is one of the situations AQA expects pupils to describe.
- A ball is thrown straight up. At launch its kinetic store holds 60 J and its gravitational potential store holds 0 J. Part-way up, its gravitational potential store holds 45 J. Ignoring air resistance, how many joules are left in its kinetic store? (number only)
15
提示With nothing lost to the air, the two stores must always add up to what the ball set off with.
为什么The system is the ball and the Earth, and no energy leaves it, so the total stays at 60 J. If 45 J has moved into the gravitational potential store, 60 − 45 is left in the kinetic store. Putting both stores on one scale like this is how AQA wants energy changes shown.
- Energy is transferred into or out of a system in three ways that GCSE pupils must be able to calculate: by ____, by work done by ____, and by work done when a current flows.
heating; forces
提示One is what a flame does to a pan of water; the other is a push or pull moving something along.
为什么Each way has its own equations later in the course: specific heat capacity for a temperature change, force × distance for mechanical work, and the electrical equations for work done in a circuit. Recognising which of the three is happening tells you which equation to reach for.
- A steady force pushes a sledge across level ice and the sledge speeds up. How is energy being transferred into the sledge's kinetic store?
By the force doing work on the sledge
提示A push that moves something along is achieving more than just pressing on it.
为什么Whenever a force moves an object through a distance, work is done and energy is transferred. Here that energy fills the sledge's kinetic store, which is why the sledge gets faster for as long as the push continues. An object accelerated by a constant force is one of AQA's named situations.
- kinetic energy = 0.5 × mass × (____)²
speed
提示Of the two things that decide how hard a moving object hits, this is the one that counts twice over.
为什么In symbols, Ek = ½ m v², with Ek in joules, m in kilograms and v in metres per second. Only the v is squared, so work out v² first and then multiply by the mass and by a half. AQA expects this equation to be recalled; it is not on the equation sheet.
- A 4 kg trolley moves at 3 m/s. Calculate its kinetic energy in joules. (number only)
18
提示Square first, then deal with the half and the 4 kg.
为什么Ek = ½ × m × v² = 0.5 × 4 × 3² = 0.5 × 4 × 9. Squaring the speed before anything else avoids the most common slip. The equation must be recalled.
- A car doubles its speed. What happens to its kinetic energy?
It becomes four times as large
提示Look at what the equation does to the quantity that has changed.
为什么Kinetic energy depends on speed squared, so doubling the speed multiplies the energy by 2², and trebling it would multiply the energy by 9. This is why a small rise in speed makes a crash so much more severe and a braking distance so much longer.
- A 2 kg ball has 100 J of kinetic energy. Calculate its speed.
10 m/s
提示Undo the equation one step at a time; the last step is a root.
为什么Rearranging Ek = ½ m v² gives v² = 2 × Ek ÷ m = 2 × 100 ÷ 2 = 100, so v is the square root of 100. Pupils are expected to recall the equation and rearrange it for any of its three quantities.
- A 1000 kg car travels at 20 m/s and a 4000 kg lorry travels at 10 m/s. Which has more kinetic energy, or are they equal?
They are equal — 200 000 J each
提示Work both out before trusting your instinct about the heavier vehicle.
为什么Car: 0.5 × 1000 × 20² = 200 000 J. Lorry: 0.5 × 4000 × 10² = 200 000 J. The lorry has four times the mass, but the car has twice the speed, and because speed is squared that also counts four times.
- The energy an object gains when it is raised above ground level
Gravitational potential energy
提示It is named after the force you have to work against to lift anything.
为什么Lifting an object means doing work against its weight, and that energy is stored because of the object's raised position. Let the object fall and the store empties again as it speeds up. Its short form is g.p.e., or Ep in equations.
- Write, in words, the equation for the gravitational potential energy gained by an object that is lifted.
g.p.e. = mass × gravitational field strength × height
提示Three things multiply together: how much stuff, how hard the planet pulls on each kilogram, and how far up.
为什么In symbols, Ep = m g h, with Ep in joules, m in kilograms, g in newtons per kilogram and h in metres. AQA expects this equation to be recalled, and says the value of g will always be given in the question.
- A 2 kg book is lifted 1.5 m onto a shelf. Gravitational field strength = 9.8 N/kg. Calculate the gravitational potential energy gained, in joules. (number only)
29.4
提示Multiply all three numbers in the question together.
为什么Ep = m × g × h = 2 × 9.8 × 1.5. The value of g is given, as AQA says it always will be. The answer is also the work done in lifting the book.
- A 50 kg climber gains 24 500 J of gravitational potential energy. Gravitational field strength = 9.8 N/kg. How high has she climbed?
50 m
提示Rearrange so the unknown stands alone, then divide the energy by the other two multiplied together.
为什么Rearranging Ep = m g h gives h = Ep ÷ (m × g) = 24 500 ÷ (50 × 9.8) = 24 500 ÷ 490. Dividing by the mass and the field strength together, rather than one at a time, saves a slip.
- A 0.5 kg ball is dropped from a height of 5 m. Take gravitational field strength as 10 N/kg and ignore air resistance. How fast is it moving just before it lands?
10 m/s
提示All the energy it had because of its position has become energy of movement by the bottom.
为什么g.p.e. at the top = 0.5 × 10 × 5 = 25 J, and with no air resistance all of it is in the kinetic store at the bottom. Then v² = 2 × 25 ÷ 0.5 = 100, so v is the square root of 100. Following energy from a gravitational store to a kinetic store is an investigation AQA suggests for this section.
1★ GCSE-PHYS-ENE-0001
2★ GCSE-PHYS-ENE-0002
3★ GCSE-PHYS-ENE-0003
4★ GCSE-PHYS-ENE-0004
5★ GCSE-PHYS-ENE-0005
6★ GCSE-PHYS-ENE-0006
7★ GCSE-PHYS-ENE-0007
8★ GCSE-PHYS-ENE-0008
9★ GCSE-PHYS-ENE-0009
10★ GCSE-PHYS-ENE-0010
11★ GCSE-PHYS-ENE-0011
12★ GCSE-PHYS-ENE-0012
13★ GCSE-PHYS-ENE-0013
14★ GCSE-PHYS-ENE-0014
15★ GCSE-PHYS-ENE-0015