- To decide whether a number such as 143 is prime, how far up do you need to test prime divisors?
Its square root
提示Any factor above that point pairs with a smaller one you would already have found.
为什么143 needs only 2, 3, 5, 7 and 11 tested (11 × 11 = 121, 13 × 13 = 169), and 11 × 13 = 143 catches it. Odd numbers between 120 and 170 are a classic trap — 143, 161 and 169 all look prime and none is. Try 3 (digit sum), then 7, 11 and 13 before declaring one prime.
- How many times a shape fits onto itself during one full turn
Its order of rotational symmetry
提示Spin it and count the matches, including the one at the end.
为什么Order 2 means a half turn works; order 4, a quarter turn. Every shape has order at least 1. A shape can have rotational symmetry with no line of symmetry, and a rectangle's centre is the point everything turns about.
- Multiplying a decimal by 10⁵ moves each digit how many places to the left? (type the number only)
5
提示One hop for every factor of ten in the power.
为什么10⁵ = 100 000, five factors of ten, so 4.25 × 10⁵ = 425 000. Digits move; the decimal point stays put. Converting kilometres to millimetres is a six-hop version of the same move.
- Which positive whole number is a factor of every number, yet never appears in a prime factorisation?
1
提示Not prime, not composite — and easy to forget that it counts as a factor.
为什么1 is not prime, so it never appears in a prime factorisation, but it is a perfectly good positive whole number. 30 = 2 × 3 × 5 = 1 × 2 × 3 × 5. Watch for the difference between 'prime factors' and 'positive whole numbers' in the wording.
- To find a fraction of a fraction — such as a third of a quarter — you ____ the two fractions.
multiply
提示The word 'of' between two fractions is an operation sign.
为什么Two thirds of three fifths is 6/15 = 2/5. When a chain of "of"s ends in a known value, reverse it by dividing by each fraction in turn — or, faster, by multiplying by each one turned upside down.
- A square grid of n by n small cells is drawn with wire. How many straight wires run in each direction?
n + 1
提示A 1 by 1 grid already needs a line on both sides.
为什么Cells and lines differ by one, like fence panels and fence posts. A 5 × 5 grid has 6 lines each way; each line is as long as the grid, so the wire needed is 2 × (n + 1) × n.
- You know the mean of a set of numbers and how many numbers there are. How do you recover their total?
Mean × number of values
提示The average is fair shares — reverse the sharing.
为什么Mean = total ÷ count, so total = mean × count. Most mean questions are really about the total: find it, subtract the parts you know, and what is left belongs to the missing values.
- Two straight lines cross. One angle is 4x and the angle beside it on the straight line is 5x, so x = ____.
20
提示Two angles side by side on a straight line make a half turn — add the expressions, then solve.
为什么Angles on a straight line add to 180°, so 4x + 5x = 180 gives 9x = 180 and x = 20. The four angles are then 80°, 100°, 80° and 100°: vertically opposite angles are equal, and each neighbouring pair adds to 180°. Once a diagram labels angles with expressions, turning it into an equation is the standard route — and with the exterior angle theorem for a triangle, those facts settle almost every angle chase in the paper.
- As fractions in their simplest form, 0.125 = ____, 0.2 = ____ and 0.375 = ____.
1/8; 1/5; 3/8
提示Write each as thousandths or ten-thousandths, then cancel.
为什么0.375 is 375/1000, which cancels to 3/8. Moving the decimal point one place divides by 10, so 1.25 = 5/4 and 0.0125 = 1/80 follow at once.
- Why can a prime number bigger than 5 never end in 0 or 5?
It would be a multiple of 5
提示Think about which times table those last digits always belong to.
为什么A number ending in 0 or 5 divides by 5, and one ending in an even digit divides by 2. So beyond the single digits every prime ends in 1, 3, 7 or 9 — the first filter to apply before testing 3 (digit sum), 7 and 11.
- The effect on a cuboid's volume of doubling all three dimensions
It is multiplied by 8
提示Each of the three directions doubles the count of unit cubes in turn.
为什么Volume = length × width × height, so doubling one dimension doubles the volume and doubling all three multiplies it by 2 × 2 × 2 = 8. A cuboid that is 2, 2 and 5 times the size of a cube in its three directions holds 2 × 2 × 5 = 20 times as many unit cubes.
- What is the smallest number with four different prime factors? (type the number only)
210
提示Small primes, each used once.
为什么Any number that is a multiple of 2, 3, 5 and 7 is a multiple of 210. Adding 1 to a product of primes is the heart of Euclid's proof that primes never run out: the result cannot be divided by any prime you multiplied, so some prime is still missing from your list.
- Dividing both numbers in a division sum by the same non-zero factor
Leaves the quotient (the answer) unchanged
提示Try it with a simple pair of numbers first, like halving both before you divide.
为什么For example, 480 ÷ 40 gives the same answer as 48 ÷ 4, because both numbers were divided by 10 first. Spotting a shared factor like this turns an awkward division into a much simpler one before you calculate — the same idea works for multiplying too.
- In a 'think of a number' puzzle, once you've expanded brackets and the unknown appears on both sides of the equation, what should you do first?
Collect all the unknown terms onto one side
提示Treat it like tidying — gather every x together before dealing with the plain numbers.
为什么For example, if 2n + 5 = 3n − 1, subtract 2n from both sides to get 5 = n − 1, then add 1 to find n = 6. Puzzles phrased as a chain of operations on "a number" almost always collapse to an equation exactly like this once you write out each step algebraically.
- When several fractions in a sum or difference all share the same denominator, you only need to combine the ____ — the denominator stays as it is.
numerators
提示Think of it as one big fraction — only the top parts need adding or subtracting.
为什么3/7 + 2/7 − 4/7 = (3 + 2 − 4)/7 = 1/7. Once every fraction in the calculation shares a denominator, treat the whole thing as ordinary addition and subtraction of the numerators, then simplify the result at the end if you can.
- When you need to count every valid arrangement in a small diagram or grid without missing one or counting it twice, what's the reliable method?
List every case in a fixed, systematic order
提示Work through the picture in the same direction each time, ticking options off as you go.
为什么Jumping between different parts of a diagram makes it easy to count a pair twice or miss one. Working left-to-right and top-to-bottom (or by size, or alphabetically) keeps every case visible exactly once, and is far more reliable under time pressure than trusting you've spotted them all.
- To check whether a given value solves an equation without solving it fresh, what do you do with that value? (one word)
Substitute
提示Pop the number straight into the equation and see if both sides balance.
为什么Solving x + 3 = 15 from scratch takes longer than simply putting a candidate value (say 12) in place of x and checking 12 + 3 = 15 is true. When a paper offers several equations and one specific number, substitution is almost always faster than solving each equation in full.
- Joining the midpoints of a triangle's three sides
Creates four congruent triangles, each a quarter of the area
提示Picture cutting a shape into identical smaller copies that all look the same as the whole.
为什么This split (the medial triangle construction) always produces four smaller triangles congruent to each other and similar to the original, each holding exactly one quarter of its area — a pattern behind many area-fraction and dissection puzzles.
- In a word problem describing two overlapping activities (some people do only one, some do both), what's the first useful algebraic step?
Give each distinct group its own letter, then link them with equations
提示Picture three separate boxes — only-A, only-B, and both — before writing anything down.
为什么For instance, if some children like only reading, some only drawing, and some both, give each group its own letter (say r, d, b), turn a phrase like 'twice as many do both as do only drawing' into an equation in those letters, then combine the equations to leave one unknown to solve.
- In a diagram built from squares packed edge-to-edge with no gaps, how do you find an unknown square's side length?
Add or subtract the lengths of the squares that touch it
提示Work outward from the smallest piece, matching up where edges meet.
为什么A 'squared rectangle' dissection is a classic puzzle: start from the smallest square, and each neighbouring square's side is fixed by the sizes of the squares beside it. Chaining these relationships outward eventually gives every side length, and multiplying the two outer sides gives the whole rectangle's area.
- Given several sum equations sharing unknowns (like row totals and column totals in a grid), a quick solving trick is to ____ two of the equations so unwanted terms ____ out.
add; cancel
提示Combining two rows or two columns together sometimes makes the unhelpful letters disappear, leaving one solvable equation.
为什么If two straight-line facts each total a known amount and both contain the same troublesome letter, adding the two equations together can make that letter's coefficients combine in a way that cancels or simplifies — sometimes solving for one unknown without ever isolating the others individually.
- The units digit of a product of two whole numbers
Depends only on the units digits of the two numbers
提示Ignore the rest of each number and multiply just their final digit.
为什么For example, 23 × 47 and 43 × 27 both end in the same digit, because 3 × 7 = 21 ends in 1 either way — swapping the other digits around does not change that. This is why comparing just the final digits of two products can quickly rule out most options in a puzzle.
- When you know the ratio between two lengths but not their actual sizes, how do you use a given total (like a perimeter) to find them?
Write each length as a multiple of one unknown, then solve for it
提示Pick a single letter for the smallest part, and express the rest of the ratio using that same letter.
为什么If two sides are always in the ratio 3:1, call the smaller one x and the larger 3x. Once you have an equation for the total — say a perimeter equal to 24 — solving it gives x, and every length follows immediately by substitution.
- If a rule bans any three consecutive places from all being filled (everyone must be alone or paired), the tightest packing repeats the block: filled, filled, ____.
empty
提示Two occupied in a row always needs a gap before the pattern can repeat safely.
为什么This is a classic 'no three in a row' packing constraint: with a repeating unit of two filled places followed by one empty place, exactly two-thirds of a long row can be filled while still satisfying the rule — the same idea behind maximising seating or parking under a no-three-together restriction.
- When a geometry diagram has too many unknown angles to find individually, what can adding two separate angle equations together sometimes achieve?
Cancel the unwanted terms, leaving a solvable combination
提示Add the two equations first and simplify before trying to solve for anything individually.
为什么If straight-line angle facts give two equations each containing the same unhelpful letter, adding the equations can make that letter combine with the angle-sum fact from a nearby triangle, cancelling it out entirely and leaving one clean equation for the angle you actually want.
1★ KS3-MATH-JMC-0073
2★ KS3-MATH-JMC-0074
3★ KS3-MATH-JMC-0075
4★ KS3-MATH-JMC-0076
5★ KS3-MATH-JMC-0077
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8★ KS3-MATH-JMC-0080
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11★ KS3-MATH-JMC-0083
12★ KS3-MATH-JMC-0084
13★ KS3-MATH-JMC-0227
14★ KS3-MATH-JMC-0228
15★ KS3-MATH-JMC-0229
16★ KS3-MATH-JMC-0230
17★ KS3-MATH-JMC-0231
18★ KS3-MATH-JMC-0232
19★ KS3-MATH-JMC-0233
20★ KS3-MATH-JMC-0234
21★ KS3-MATH-JMC-0235
22★ KS3-MATH-JMC-0236
23★ KS3-MATH-JMC-0237
24★ KS3-MATH-JMC-0238
25★ KS3-MATH-JMC-0239