Chemistry · Professor Curie

Quantitative chemistry, Year 10: reacting masses, limiting reactants and concentration:全部卡片

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1 GCSE-CHEM-QUA-0016

Mg + 2HCl → MgCl2 + H2. How many moles of hydrochloric acid react completely with 3 mol of magnesium? (number only)

6

提示The big numbers in front of the formulae give the recipe.

为什么The equation says that one mole of magnesium reacts with two moles of hydrochloric acid. Three moles of magnesium therefore need 3 × 2 moles of acid.

2 GCSE-CHEM-QUA-0017

2Mg + O2 → 2MgO. (Ar: Mg = 24, O = 16.) 12 g of magnesium is ____ mol of Mg, which forms ____ mol of MgO, which has a mass of ____ g.

0.5; 0.5; 20

提示Three steps: grams to moles, then the ratio in the equation, then moles back to grams.

为什么Moles of Mg = 12 ÷ 24. The equation shows 2 mol of Mg making 2 mol of MgO, a 1 : 1 ratio. The Mr of MgO is 24 + 16 = 40, so the mass is the moles of MgO × 40.

3 GCSE-CHEM-QUA-0018

N2 + 3H2 → 2NH3. What mass of hydrogen does this equation show reacting with 28 g of nitrogen? Use Ar: N = 14, H = 1.

6 g

提示28 g is exactly one mole of N2, so read the amounts straight from the balancing numbers.

为什么One mole of N2 has a mass of 2 × 14 = 28 g. It reacts with three moles of H2, and each mole of H2 has a mass of 2 × 1 = 2 g, so the mass of hydrogen is 3 × 2 g.

4 GCSE-CHEM-QUA-0019

For the reaction Mg + 2HCl → MgCl2 + H2, a pupil says that 10 g of magnesium must react with 20 g of hydrochloric acid. Why is this wrong?

The 2 is a ratio of moles, not of masses

提示Balancing numbers count particles, and the particles of the two substances do not weigh the same.

为什么The equation says 1 mol of Mg reacts with 2 mol of HCl. In grams that is 24 g of magnesium with 2 × 36.5 = 73 g of hydrogen chloride. Masses have to be turned into moles before the ratio can be used.

5 GCSE-CHEM-QUA-0020

Fe2O3 + 3CO → 2Fe + 3CO2. What mass of iron(III) oxide is needed to make 112 g of iron? Use Ar: Fe = 56, O = 16.

160 g

提示Work backwards: turn the product into moles first, then use the ratio to find the reactant.

为什么Moles of Fe = 112 ÷ 56 = 2. The equation shows 1 mol of Fe2O3 giving 2 mol of Fe, so 1 mol of Fe2O3 is needed. Its Mr is (2 × 56) + (3 × 16) = 160, so the mass is 160 g.

6 GCSE-CHEM-QUA-0021

To work out the balancing numbers of an equation from the masses that reacted, first convert each mass in grams into an amount in ____.

moles

提示Balancing numbers count particles, so you need the chemist's counting unit.

为什么Divide each mass by the relative formula mass of that substance. The amounts you get are then turned into the simplest whole-number ratio, and those whole numbers are the balancing numbers.

7 GCSE-CHEM-QUA-0022

5.6 g of nitrogen, N2 (Mr 28), reacts with 1.2 g of hydrogen, H2 (Mr 2), to make 6.8 g of ammonia, NH3 (Mr 17). That is ____ mol of N2, ____ mol of H2 and ____ mol of NH3, so the balanced equation is N2 + ____H2 → 2NH3.

0.2; 0.6; 0.4; 3

提示Divide each mass by its Mr, then divide all three results by the smallest.

为什么Moles = mass ÷ Mr for each substance. Dividing the three amounts by the smallest gives the ratio 1 : 3 : 2, and these are the balancing numbers.

8 GCSE-CHEM-QUA-0023

In a reaction, 0.4 mol of aluminium reacts with 0.6 mol of chlorine, Cl2. What is the simplest whole-number ratio of Al to Cl2?

2 : 3

提示Dividing by the smaller amount leaves a half in the ratio, so scale up once more.

为什么Dividing both amounts by 0.4 gives 1 : 1.5. Balancing numbers must be whole, so multiply both by 2. The equation is 2Al + 3Cl2 → 2AlCl3.

9 GCSE-CHEM-QUA-0024

When turning amounts in moles into balancing numbers, why do you start by dividing every amount by the smallest one?

To get the simplest whole-number ratio

提示Amounts such as 0.2 and 0.6 are in the right proportion, but an equation is never written with them.

为什么Dividing by the smallest amount turns it into 1 and scales the others to match, which usually gives whole numbers straight away. If a half appears, doubling everything clears it.

10 GCSE-CHEM-QUA-0025

0.5 mol of a gas has a mass of 22 g. What is its relative formula mass? (number only)

44

提示Rearrange moles = mass ÷ Mr so that Mr is the subject.

为什么Multiplying both sides of moles = mass ÷ Mr by Mr and then dividing by moles gives Mr = mass ÷ moles = 22 ÷ 0.5. The specification expects you to be able to change the subject of an equation like this.

11 GCSE-CHEM-QUA-0026

The reactant that is completely used up in a reaction, so that it decides how much product can form

The limiting reactant

提示Its name comes from the fact that it sets a ceiling on what can be made.

为什么Once this reactant has run out, the reaction stops, however much of the other reactant is left. The amount of product therefore depends on how much of it there was at the start.

12 GCSE-CHEM-QUA-0027

One reactant is often added in ____ to make sure that all of the other reactant is used up.

excess

提示It means more than is needed.

为什么If there is more than enough of one reactant, the other one is certain to react completely. The one that is used up is then the limiting reactant, and some of the other is left over at the end.

13 GCSE-CHEM-QUA-0028

Mg + 2HCl → MgCl2 + H2. 0.1 mol of magnesium is added to 0.3 mol of hydrochloric acid. Which reactant is limiting, and why?

Magnesium: it needs only 0.2 mol of acid, so acid is left over

提示Use the ratio in the equation to see how much of one the other requires.

为什么0.1 mol of magnesium reacts with 0.1 × 2 = 0.2 mol of acid. There is 0.3 mol of acid, more than enough, so the magnesium runs out first and 0.1 mol of acid is left unreacted.

14 GCSE-CHEM-QUA-0029

Magnesium is the limiting reactant when it is added to an excess of acid. What happens to the amount of hydrogen produced if the amount of acid is doubled?

It stays the same

提示Ask which substance runs out first, and whether that has changed.

为什么The amount of product is set by the limiting reactant. The magnesium still runs out at the same point, so the same amount of hydrogen is made; there is simply more acid left over.

15 GCSE-CHEM-QUA-0030

CaCO3 + 2HCl → CaCl2 + H2O + CO2. 10 g of calcium carbonate is added to an excess of hydrochloric acid. What is the maximum mass of carbon dioxide that can form, in grams? Use Ar: Ca = 40, C = 12, O = 16. (number only)

4.4

提示The acid is plentiful, so only the solid decides the answer: grams to moles, ratio, moles to grams.

为什么Calcium carbonate is the limiting reactant. Its Mr is 40 + 12 + (3 × 16) = 100, so 10 g is 0.1 mol. The equation gives 1 mol of CO2 per mole of CaCO3, so 0.1 mol of CO2 forms, with a mass of 0.1 × 44.

16 GCSE-CHEM-QUA-0031

Concentration in g/dm³ = mass of solute in grams ÷ ____ of solution in dm³.

volume

提示It is the amount of space the solution takes up.

为什么Concentration says how much solute is packed into each unit of solution. More solute in the same space, or the same solute in less space, both give a more concentrated solution.

17 GCSE-CHEM-QUA-0032

How many cubic centimetres are there in one cubic decimetre? (number only)

1000

提示A decimetre is 10 cm, and a cube has three dimensions.

为什么A cube 10 cm along each edge holds 10 × 10 × 10 cubic centimetres. One cubic decimetre is the same volume as one litre.

18 GCSE-CHEM-QUA-0033

250 cm³ is ____ dm³, so 250 cm³ of a solution with a concentration of 60 g/dm³ contains ____ g of solute.

0.25; 15

提示Convert the volume first, then multiply by how much each whole cubic decimetre holds.

为什么Divide by 1000 to change cm³ into dm³. Then mass of solute = concentration × volume = 60 × 0.25. This is the concentration equation rearranged to make mass the subject.

19 GCSE-CHEM-QUA-0034

20 g of sugar is dissolved in water to make 500 cm³ of solution. What is the concentration in g/dm³? (number only)

40

提示Change the volume into cubic decimetres before you divide.

为什么500 cm³ is 0.5 dm³, and 20 ÷ 0.5 = 40. Another way to see it: a whole cubic decimetre is twice as much solution, so it would hold twice as much sugar.

20 GCSE-CHEM-QUA-0035

A solution has a concentration of 20 g/dm³. Water is evaporated until its volume has halved, and no solute is lost. What is the new concentration, and why?

40 g/dm³: the same mass is in half the volume

提示Think about what happens to the result of a division when the number you divide by gets smaller.

为什么Concentration = mass ÷ volume. The mass of solute has not changed, but it is now divided by half the volume, so the answer doubles. In the same way, doubling the mass of solute in the same volume doubles the concentration.

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