Mathematics

Number, Year 11: bounds, growth and compound interest

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MathematicsNumber, Year 11: bounds, growth and compound interest
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Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
↔ 正反两问先在心里作答…For a measurement that has been rounded, the top end of its error interval: the value the true measurement must be less than
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★ GCSE-MATH-NUM-0046正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

The upper bound of a rounded measurement

提示A two-word name; its partner at the other end is called 'lower'.

为什么A length of 7.4 cm to 1 decimal place lies in 7.35 ≤ L < 7.45, so this value is 7.45 cm. The true length can get as close to it as you like but cannot equal it, because 7.45 would round to 7.5.

★ GCSE-MATH-NUM-0046背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…A rectangle measures 6 cm by 4 cm, each to the nearest centimetre. Work out the upper bound for its area.
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★ GCSE-MATH-NUM-0047正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

29.25 cm²

提示Make both sides as long as they could possibly be before multiplying.

为什么Each side could be up to half a centimetre longer: 6.5 cm and 4.5 cm. The largest possible area is 6.5 × 4.5 = 29.25 cm². The lower bound is 5.5 × 3.5 = 19.25 cm².

★ GCSE-MATH-NUM-0047背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…p = 8.4 and q = 2.6, each correct to 1 decimal place. To get the greatest possible value of p − q, which bound of p and which bound of q should you use?
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★ GCSE-MATH-NUM-0048正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

The upper bound of p and the lower bound of q

提示Taking away less leaves more.

为什么The difference is biggest when you start with as much as possible and remove as little as possible: 8.45 − 2.55 = 5.9. For the least possible difference, swap the bounds: 8.35 − 2.65 = 5.7.

★ GCSE-MATH-NUM-0048背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
⌨ 打字作答先在心里作答…A car travels 100 m, measured to the nearest 10 m, in 8 s, measured to the nearest second. Work out the upper bound for its average speed in m/s. (number only)

★ GCSE-MATH-NUM-0049正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

14

提示Speed is greatest when the distance is as long as possible and the time as short as possible.

为什么Upper bound of distance = 105 m; lower bound of time = 7.5 s. Greatest speed = 105 ÷ 7.5 = 14 m/s. In a division, use the upper bound on top and the lower bound underneath to get the largest answer.

★ GCSE-MATH-NUM-0049背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…A calculated length has lower bound 2.4612 m and upper bound 2.4649 m. To what degree of accuracy can the length be stated with certainty, and what is it to that accuracy?
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★ GCSE-MATH-NUM-0050正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

2.46 m, to 2 decimal places (3 significant figures)

提示Round both ends more and more finely and see where they stop agreeing.

为什么To 2 decimal places both bounds give 2.46, so every possible value rounds to 2.46. To 3 decimal places they give 2.461 and 2.465, which differ, so the third decimal place is not certain.

★ GCSE-MATH-NUM-0050背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
⌨ 打字作答先在心里作答…A price rises by 10% and is then reduced by 10%. What single decimal multiplier gives the overall change? (number only)

★ GCSE-MATH-NUM-0051正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

0.99

提示Write each change as its own multiplier, then combine the two.

为什么The rise is × 1.1 and the reduction is × 0.9, and 1.1 × 0.9 = 0.99, an overall fall of 1%. For example £200 becomes £220 and then £198. The 10% reduction is taken from the larger amount, so it removes more than the rise added.

★ GCSE-MATH-NUM-0051背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…A car is bought for £12 000. It loses 20% of its value each year. Work out its value after 2 years.
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★ GCSE-MATH-NUM-0052正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

£7680

提示Each year's loss is 20% of what the car is worth at the start of that year.

为什么Losing 20% leaves 80%, a multiplier of 0.8. After two years the value is 12 000 × 0.8 × 0.8 = 12 000 × 0.8² = £7680. Year by year: £9600, then £7680.

★ GCSE-MATH-NUM-0052背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
↔ 正反两问先在心里作答…The fall in the value of something, such as a car or a computer, as it gets older
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★ GCSE-MATH-NUM-0053正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

Depreciation

提示It is the opposite of 'appreciation', a rise in value.

为什么A car that loses 15% of its value each year is depreciating at 15% a year, so each year its value is multiplied by 0.85. It is a decay problem: the same percentage is lost each year, so the amount lost in pounds gets smaller every year.

★ GCSE-MATH-NUM-0053背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
填空先在心里作答…To decrease an amount by 15% again and again, multiply repeatedly by the decimal multiplier ____.
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★ GCSE-MATH-NUM-0054正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

0.85

提示Ask what percentage of the amount is left after the decrease.

为什么Taking away 15% leaves 85% of the amount, and 85% as a decimal is 0.85. Three decreases in a row multiply by 0.85³. A multiplier below 1 means decay; one above 1 means growth.

★ GCSE-MATH-NUM-0054背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…A town has a population of 20 000. The population grows by 10% each year. Work out the population after 3 years.
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★ GCSE-MATH-NUM-0055正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

26 620

提示Use a single multiplier for one year's growth, and apply it once for each year.

为什么A 10% increase is a multiplier of 1.1. After 3 years the population is 20 000 × 1.1³ = 20 000 × 1.331 = 26 620. Year by year: 22 000, 24 200, 26 620.

★ GCSE-MATH-NUM-0055背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
多处填空先在心里作答…£2000 is invested at 5% compound interest per year. After one year the account holds £____, and after two years it holds £____.
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★ GCSE-MATH-NUM-0056正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

2100; 2205

提示Each year's interest is worked out on whatever is in the account at the start of that year.

为什么Year 1: 2000 × 1.05 = £2100. Year 2 starts from £2100, not £2000: 2100 × 1.05 = £2205. The second year earns £105, which is £5 more than the first, because the first year's £100 of interest earns interest too.

★ GCSE-MATH-NUM-0056背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…£500 is invested at 4% compound interest per year. Write the single calculation that gives the amount in the account after 6 years, using a multiplier and a power. You do not need to work it out.
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★ GCSE-MATH-NUM-0057正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

500 × 1.04⁶

提示Adding four per cent is the same as multiplying by one number; do that once for every year.

为什么Adding 4% multiplies an amount by 1.04. Doing that six years running multiplies by 1.04 six times, which is 1.04⁶. On a calculator this gives £632.66 to the nearest penny.

★ GCSE-MATH-NUM-0057背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
⌨ 打字作答先在心里作答…A savings account pays 10% compound interest per year. £1000 is invested and left alone. After how many complete years does the balance first go above £1300? (number only)

★ GCSE-MATH-NUM-0058正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

3

提示Build the balance up one year at a time, multiplying by the same number each year.

为什么Each year multiplies the balance by 1.1: £1100 after one year, £1210 after two and £1331 after three. The balance first passes £1300 at the end of the third year.

★ GCSE-MATH-NUM-0058背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
先在心里作答…£1000 is invested for 2 years at 10% per year. How much more does it earn with compound interest than with simple interest, and where does the extra come from?
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★ GCSE-MATH-NUM-0059正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

£10 more — in the second year, interest is also paid on the first year's £100 of interest

提示Find both totals, then ask what the later 10% is being taken of in each case.

为什么Simple interest: £100 each year, £200 in all. Compound interest: £100 in year one, then 10% of £1100 = £110 in year two, £210 in all. The £10 difference is 10% of the first year's £100 of interest.

★ GCSE-MATH-NUM-0059背面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi
↔ 正反两问先在心里作答…Interest that is worked out each time on the original amount plus all the interest already added
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★ GCSE-MATH-NUM-0060正面

Mathematics · Number, Year 11: bounds, growth and compound interestProfessor Pi

Compound interest

提示Its name means 'made of parts put together'; the other kind is called simple.

为什么Because each year's interest joins the balance and then earns interest itself, the amount grows by the same multiplier every year, not by the same number of pounds. Simple interest is always worked out on the original amount only.

★ GCSE-MATH-NUM-0060背面

Number, Year 11: bounds, growth and compound interest

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