Mathematics

JMC 2016

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MathematicsJMC 2016
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Mathematics · JMC 2016Professor Pi
Answer in your head…In the calculation 2 + 3 × 4², which operation is done first?
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★ KS3-MATH-JMC-0025Front

Mathematics · JMC 2016Professor Pi

The squaring

HintIndices come before multiplication in the order of operations, and both come before addition.

The whyIndices come first, then multiplication and division, then addition and subtraction: 2 + 3 × 4² = 2 + 3 × 16 = 50, not (2 + 3) × 4² = 80 and not 2 + (3 × 4)² = 146. Competition papers open with a question like this most years, and the trap is always reading left to right.

★ KS3-MATH-JMC-0025Back

Mathematics · JMC 2016Professor Pi
Answer in your head…Every term in a long sum shares the same factor, such as 3 + 6 + 9 + 12 + … What is the quickest first move?
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★ KS3-MATH-JMC-0026Front

Mathematics · JMC 2016Professor Pi

Factorise it first

HintPull the shared number out in front of a bracket.

The why3 + 6 + 9 + 12 = 3 × (1 + 2 + 3 + 4). When such a sum sits over another sum in a fraction, the bracket often cancels completely and the whole thing collapses to a single number — no adding required.

★ KS3-MATH-JMC-0026Back

Mathematics · JMC 2016Professor Pi
⌨ Type the answerAnswer in your head…How many lines of symmetry does a regular hexagon have? (type the number only)

★ KS3-MATH-JMC-0027Front

Mathematics · JMC 2016Professor Pi

6

HintSome pass through opposite corners, others through the midpoints of opposite edges — count both kinds.

The whyA regular polygon with n sides has n lines of symmetry: for a hexagon, three join pairs of opposite vertices and three join the midpoints of opposite sides. Folding a shape exactly in half means folding along a line of symmetry, so every 'fold in half' question starts by finding those lines.

★ KS3-MATH-JMC-0027Back

Mathematics · JMC 2016Professor Pi
Answer in your head…Without dividing, how do you decide whether a large number is a multiple of 4?
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★ KS3-MATH-JMC-0028Front

Mathematics · JMC 2016Professor Pi

Check its last two digits

Hint100 is a multiple of 4, so the hundreds and above never matter.

The whyA number is a multiple of 4 exactly when the number formed by its final two digits is. 5678 ends in 78, which is not a multiple of 4, so 5678 is not either — even though it is even. The matching test for 8 uses the final three digits.

★ KS3-MATH-JMC-0028Back

Mathematics · JMC 2016Professor Pi
Answer in your head…Years that are multiples of 4 are leap years — except for century years. Which century years ARE leap years?
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★ KS3-MATH-JMC-0029Front

Mathematics · JMC 2016Professor Pi

Multiples of 400

Hint1900 was not one; 2000 was.

The whyThe rule: a leap year is a multiple of 4, unless it is a multiple of 100, unless it is also a multiple of 400. So 1900 and 2100 are ordinary years while 2000 and 2400 are leap years. Time questions that span centuries depend on it.

★ KS3-MATH-JMC-0029Back

Mathematics · JMC 2016Professor Pi
↔ Asked both waysAnswer in your head…Where the equal angles of an isosceles triangle sit
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★ KS3-MATH-JMC-0030Front

Mathematics · JMC 2016Professor Pi

Opposite the equal sides

HintLook where the two same-length legs point: the matching angles are at their far ends.

The whyThe equal angles are opposite the equal sides, never between them. Spotting an isosceles triangle in a diagram gives you an equal pair of angles for free, and combined with the angle sum of 180° that often solves the whole question.

★ KS3-MATH-JMC-0030Back

Mathematics · JMC 2016Professor Pi
Fill the gapAnswer in your head…The sum of the first n cube numbers — 1³ + 2³ + … + n³ — is always a ____ number.
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★ KS3-MATH-JMC-0031Front

Mathematics · JMC 2016Professor Pi

square

Hint1 + 8 = 9 and 1 + 8 + 27 = 36: what kind of numbers are those?

The why1 + 8 + 27 + 64 = 100 = 10², and in general the sum equals (1 + 2 + … + n)². The pattern is worth knowing as a fact; proving it is a lovely investigation.

★ KS3-MATH-JMC-0031Back

Mathematics · JMC 2016Professor Pi
↔ Asked both waysAnswer in your head…Rotational symmetry of order 2
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★ KS3-MATH-JMC-0032Front

Mathematics · JMC 2016Professor Pi

Looks the same after a half turn

HintSpin the page through 180° and compare.

The whyA shape can have rotational symmetry without any line of symmetry — the letter S is the classic example. In grid-colouring questions, order-2 symmetry means every cell must match the cell opposite it through the centre. Only a grid with an odd number of rows and an odd number of columns has a middle cell that maps onto itself, so only there is one cell free to be any colour; in a 4 by 4 grid every cell is paired with another.

★ KS3-MATH-JMC-0032Back

Mathematics · JMC 2016Professor Pi
Fill the gapAnswer in your head…Two shares are in the ratio 3 : 7 and one is 24 more than the other, so the smaller share is ____.
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★ KS3-MATH-JMC-0033Front

Mathematics · JMC 2016Professor Pi

18

HintThe gap between the shares covers the difference in parts, so work out what a single part is worth first.

The whyRatio questions arrive in three flavours: you are given the total, one share, or the difference. Here 7 − 3 = 4 parts are worth 24, so one part is 6 and the shares are 18 and 42, totalling 60. Naming what one part is worth turns every flavour into one multiplication. Beware also that one share as a fraction of the whole has the TOTAL of the parts underneath: in 2 : 7 the first share is 2 out of 9, not 2 out of 7.

★ KS3-MATH-JMC-0033Back

Mathematics · JMC 2016Professor Pi
⌨ Type the answerAnswer in your head…Write 1/40 as a decimal. (type the number only)

★ KS3-MATH-JMC-0034Front

Mathematics · JMC 2016Professor Pi

0.025

HintScale the fraction so its denominator becomes 1000.

The why1/40 = 25/1000 = 0.025. Any fraction whose denominator divides a power of ten converts this way: 1/8 = 0.125, 1/20 = 0.05, 3/50 = 0.06.

★ KS3-MATH-JMC-0034Back

Mathematics · JMC 2016Professor Pi
Fill the gapsAnswer in your head…There are ____ seconds in an hour, ____ minutes in a day and ____ hours in an ordinary year.
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★ KS3-MATH-JMC-0035Front

Mathematics · JMC 2016Professor Pi

3600; 1440; 8760

HintMultiply the everyday counts together, one step at a time.

The whyEach is a product of the familiar units: 60 × 60, 24 × 60 and 365 × 24. 'How long is this?' questions reward converting step by step rather than all at once — and a leap year has 8784 hours.

★ KS3-MATH-JMC-0035Back

Mathematics · JMC 2016Professor Pi
Answer in your head…You build an arrangement by making one choice, then another, then another. Each choice is independent of the others. How do you count the total number of arrangements?
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★ KS3-MATH-JMC-0036Front

Mathematics · JMC 2016Professor Pi

Multiply the counts

HintTwo options followed by three options gives six routes through the tree.

The whyIndependent choices multiply: 2 shirts, 3 pairs of trousers and 4 hats give 2 × 3 × 4 = 24 outfits. Add only when the options are alternatives to each other, never when the choices happen one after another.

★ KS3-MATH-JMC-0036Back

Mathematics · JMC 2016Professor Pi
Answer in your head…In a multiple-choice sum or subtraction, how can working out just one column of the calculation sometimes single out the right option?
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★ KS3-MATH-JMC-0171Front

Mathematics · JMC 2016Professor Pi

Work out just the final digit

HintOnly the ones column decides it — find that one figure and match it to an option.

The whySubtracting or adding within the last column of a sum determines the final digit of the result, and that's often enough to eliminate every wrong option in a multiple-choice list — even before you've worked out the full number. It works best when a carry or borrow only needs tracking one column deep, and it's no substitute for full working when the options share a units digit.

★ KS3-MATH-JMC-0171Back

Mathematics · JMC 2016Professor Pi
Answer in your head…A real quantity is divided and the answer isn't a whole number. What does the leftover actually represent?
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★ KS3-MATH-JMC-0172Front

Mathematics · JMC 2016Professor Pi

Part of one whole share

HintExpress the leftover using the divisor as the denominator, not by rounding it off.

The whySharing 250 sweets into bags of 40 gives 6.25 bags — the .25 isn't an error, it's exactly a quarter of one more bag, since dividing by 40 always writes the remainder over 40 as the denominator. Competition and exam questions often want that precise fractional value rather than a number rounded up or down, so check what the question is actually asking before you round.

★ KS3-MATH-JMC-0172Back

Mathematics · JMC 2016Professor Pi
Fill the gapsAnswer in your head…When a calculation spans a huge range, ____ through a landmark number instead of leaping straight there; when a sequence follows a repeating rule, ____ it term by term instead of jumping to a formula.
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★ KS3-MATH-JMC-0173Front

Mathematics · JMC 2016Professor Pi

bridge; iterate

HintBreak the big problem into smaller, checkable pieces — one step, or one landmark, at a time.

The whyTwo techniques share this idea: bridging a big subtraction through the nearest round number (rather than subtracting straight across a long span) breaks one hard sum into two easy ones, and building a sequence term-by-term from a repeating rule — each new term made from the ones before it — avoids needing a closed formula. Both trade one big leap for several small, checkable steps.

★ KS3-MATH-JMC-0173Back

Mathematics · JMC 2016Professor Pi
Answer in your head…You know the total of two quantities and how much bigger one is than the other. What's the quickest way to find both quantities?
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★ KS3-MATH-JMC-0174Front

Mathematics · JMC 2016Professor Pi

Add or subtract half the difference from half the total

HintPicture two equal piles, then move enough between them to create the gap.

The whyIf two amounts sum to S and differ by D, the larger is S/2 + D/2 and the smaller is S/2 − D/2 — split the amount evenly then shift each side by half the gap between them. It turns a two-unknown word problem into pure arithmetic, with no equation needed.

★ KS3-MATH-JMC-0174Back

Mathematics · JMC 2016Professor Pi
Answer in your head…You're given one approximate conversion, like 3 kg being about 6.6 lb. How do you use it to convert a different mass to the same units?
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★ KS3-MATH-JMC-0175Front

Mathematics · JMC 2016Professor Pi

Scale the given ratio by the same factor

HintFind what one of the stated units is worth, then multiply by however many you actually have.

The whyTurn '3 kg ≈ 6.6 lb' into a rate — 1 kg ≈ 2.2 lb — then multiply that rate by whatever new mass you're converting. This unitary method works for any pair of quantities that scale together: recipes, exchange rates, speeds.

★ KS3-MATH-JMC-0175Back

Mathematics · JMC 2016Professor Pi
Answer in your head…A problem allows only a handful of possible operations or arrangements. What's the safest way to check which outcomes are actually achievable?
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★ KS3-MATH-JMC-0176Front

Mathematics · JMC 2016Professor Pi

Write out every case and check it

HintWork through the possibilities systematically instead of guessing which one looks right.

The whyWhen there are only a handful of positions and operations to try, it's faster and safer to write out every case and check it against the question than to search for a shortcut or trust a guess. Skipping just one case can make you wrongly rule out an answer that was actually achievable.

★ KS3-MATH-JMC-0176Back

Mathematics · JMC 2016Professor Pi
↔ Asked both waysAnswer in your head…The piece to place first in a constraint-satisfaction puzzle
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★ KS3-MATH-JMC-0177Front

Mathematics · JMC 2016Professor Pi

Whichever piece has the fewest valid options

HintFind the item that has the least room to manoeuvre, and lock it in before anything else.

The whySome items in a constraint puzzle can only go in one or two places because of the rules, while others have many choices. Pinning down the most restricted item first usually forces the rest of the puzzle into place with far less trial and error.

★ KS3-MATH-JMC-0177Back

Mathematics · JMC 2016Professor Pi
Answer in your head…In a digit-substitution addition puzzle, a column's digits seem to give a result too big to just be their sum. What's really happening?
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★ KS3-MATH-JMC-0178Front

Mathematics · JMC 2016Professor Pi

A carry is coming in from the column before

HintRemember an extra 1 often slips in beside it, on top of what you already see.

The whyColumn addition sometimes produces a result that looks impossible until you remember a carry from the previous column adds an extra 1 (or more) before the column's own digits are combined. Spotting where a carry MUST occur — because the visible digits alone can't produce the given answer — is often the key move that pins down an unknown digit in these puzzles.

★ KS3-MATH-JMC-0178Back

Mathematics · JMC 2016Professor Pi
Fill the gapAnswer in your head…To avoid fractions when a word problem describes a fifth of an unknown amount, let the variable stand for a whole ____ of five.
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★ KS3-MATH-JMC-0179Front

Mathematics · JMC 2016Professor Pi

multiple

HintChoose your letter so the fraction divides it exactly, with nothing left over.

The whyIf a problem says a fifth of some amount, let the unknown be 5 times a smaller unit (e.g. 5n objects) rather than n objects itself — then a fifth is exactly n, with no fraction to carry through the rest of the working. Choosing a variable that's a multiple of the denominator is a standard way to keep an algebraic solution fraction-free.

★ KS3-MATH-JMC-0179Back

Mathematics · JMC 2016Professor Pi
⌨ Type the answerAnswer in your head…Some area formulas for polygons use half the total perimeter as a building block. What is that quantity called? (type the term only)

★ KS3-MATH-JMC-0180Front

Mathematics · JMC 2016Professor Pi

Semi-perimeter

HintIt's simply the total distance around the shape, cut in half.

The whyThe semi-perimeter, usually written s, is half of a shape's total perimeter. It's the key ingredient in formulas like Heron's formula for a triangle's area and Brahmagupta's formula for a cyclic quadrilateral's area — both build the area from s and the shape's side lengths.

★ KS3-MATH-JMC-0180Back

Mathematics · JMC 2016Professor Pi
Answer in your head…An irregular shape's area is awkward to compute directly, but it's almost a simple shape with a bite taken out. What's the strategy?
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★ KS3-MATH-JMC-0181Front

Mathematics · JMC 2016Professor Pi

Find the simple shape's area and subtract the missing part

HintComplete the awkward outline into a figure you already know how to measure, and take away what shouldn't be there.

The whyComposite-area problems often become easy once you spot that the shape is 'a rectangle minus a triangle' or 'a square minus a corner' rather than something with no known formula. Work out the area of the larger, complete shape, then subtract the piece that was removed — using the triangle-area formula (half the base times the height) for any missing triangular corner.

★ KS3-MATH-JMC-0181Back

Mathematics · JMC 2016Professor Pi
Answer in your head…When identical shapes are joined edge-to-edge to build a bigger figure, which edges vanish from the final perimeter?
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★ KS3-MATH-JMC-0182Front

Mathematics · JMC 2016Professor Pi

Whichever edges sit on the inside joins

HintOnly the outer boundary counts — any edge glued to a neighbour disappears from the outline.

The whyEvery edge used to join two copies together becomes an internal seam, not part of the final perimeter. To make the perimeter as large as possible, choose joins that hide the SHORTEST edges internally, leaving the longest edges on the outside boundary — and to make it as small as possible, do the reverse.

★ KS3-MATH-JMC-0182Back

Mathematics · JMC 2016Professor Pi
Answer in your head…A board has an odd number of squares, and each tile you place covers exactly two of them. What can you say about the number of squares left uncovered, however the tiles are placed?
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★ KS3-MATH-JMC-0183Front

Mathematics · JMC 2016Professor Pi

It's always an odd number

HintCovered squares come in twos each time, so taking an even amount away from an odd total can't leave an even amount.

The whyWhatever pattern the tiles make, the covered squares always total an even number (two per tile). Subtracting an even number from a fixed total preserves whether that total is odd or even — so on a board with an odd number of squares in total, the leftover uncovered squares must also be odd, ruling out any even option immediately. This kind of parity argument is a powerful shortcut in tiling and covering problems generally.

★ KS3-MATH-JMC-0183Back

JMC 2016

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