Mathematics

IMC 2016

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MathematicsIMC 2016
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Mathematics · IMC 2016Professor Pi
Answer in your head…Which single test decides divisibility by both 3 and 9?
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KS3-MATH-IMC-0025Front

Mathematics · IMC 2016Professor Pi

The digit sum

HintNot the final column — all the columns together.

The whyAdd the digits (and, if the total is still large, add again): a total that is a multiple of 3 means the number is, and a multiple of 9 means the number is. Because sums and differences of multiples of 9 are multiples of 9, the test also catches arithmetic slips.

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KS3-MATH-IMC-0025Back

Mathematics · IMC 2016Professor Pi
↔ Asked both waysAnswer in your head…The smallest number that is a multiple of both of two given numbers
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KS3-MATH-IMC-0026Front

Mathematics · IMC 2016Professor Pi

Lowest common multiple

HintTwo events repeat on different cycles; when do they first happen together?

The whySomething that happens every 4 days and a weekday that comes round every 7 days next coincide after the lowest common multiple of 4 and 7, which is 28 days. When the two numbers share no factor, the LCM is simply their product; when they do, it is smaller.

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KS3-MATH-IMC-0026Back

Mathematics · IMC 2016Professor Pi
⌨ Type the answerAnswer in your head…How many seconds are there in one hour? (type the number only)

KS3-MATH-IMC-0027Front

Mathematics · IMC 2016Professor Pi

3600

HintThink of it as minutes, then go one level finer.

The whySpeed questions that mix metres per second with kilometres per hour need this number: multiply a speed in m/s by 3600 to get metres per hour, then divide by 1000 for km/h — so the whole conversion is × 3.6. For an approximate answer, round the awkward numbers first.

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KS3-MATH-IMC-0027Back

Mathematics · IMC 2016Professor Pi
Fill the gapAnswer in your head…The interior angles of a hexagon add up to ____°.
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KS3-MATH-IMC-0028Front

Mathematics · IMC 2016Professor Pi

720

HintCut it into triangles from one corner and count them.

The whyFour triangles from one vertex, each 180°, gives 720° — the formula 180(n − 2) with n = 6. When an angle is marked round the outside of a vertex, swap it for 360° minus it (an exterior angle proper is 180° minus the interior), then use this total.

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KS3-MATH-IMC-0028Back

Mathematics · IMC 2016Professor Pi
Answer in your head…Two angles inside a quadrilateral, at the two ends of one side, add up to 180°. What does that tell you about the two sides leaving that side?
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KS3-MATH-IMC-0029Front

Mathematics · IMC 2016Professor Pi

They are parallel

HintCo-interior angles behave this way for exactly one kind of pair of lines.

The whyAngles that add to 180° between two lines and a transversal mean the lines are parallel — and if the other pair does not add to 180°, those sides are not. One pair parallel and the other not is the definition of a trapezium, which is how a quadrilateral can be classified from its angles alone.

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KS3-MATH-IMC-0029Back

Mathematics · IMC 2016Professor Pi
Answer in your head…How do you check from a number's prime factorisation whether it is a multiple of 24?
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KS3-MATH-IMC-0030Front

Mathematics · IMC 2016Professor Pi

Contains 2³ × 3

HintFactorise the divisor first, then look for every one of its prime powers.

The whyA number is a multiple of d exactly when its prime factorisation contains every prime power in d's. For 24 that means at least three 2s and at least one 3; 2² × 3² × 5 fails, however large the other powers are. The same check works for any divisor you can factorise.

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KS3-MATH-IMC-0030Back

Mathematics · IMC 2016Professor Pi
Answer in your head…How do you find the area of an annulus (the ring between two circles with the same centre)?
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KS3-MATH-IMC-0031Front

Mathematics · IMC 2016Professor Pi

Big circle minus small circle

HintTwo discs, one take-away.

The whyRing areas are a subtraction of two circle areas: π(R² − r²), which factorises as π(R + r)(R − r). Keep the π as a common factor to the end — it usually cancels or stays in the answer.

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KS3-MATH-IMC-0031Back

Mathematics · IMC 2016Professor Pi
Fill the gapsAnswer in your head…The ____ is the most frequent value, the ____ is the middle value once the list is in order, and the ____ is the total shared out equally.
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KS3-MATH-IMC-0032Front

Mathematics · IMC 2016Professor Pi

mode; median; mean

HintMost common, middle, and fair share — three different words.

The whyQuestions that give a mode, a median and a mean and ask for the smallest or largest possible value are logic puzzles built on these definitions: a mode must appear at least twice, a median splits the ordered list in half, and a mean fixes the total. Each fact forces something about the list.

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KS3-MATH-IMC-0032Back

Mathematics · IMC 2016Professor Pi
Answer in your head…What is special about the two diagonals of a rhombus?
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KS3-MATH-IMC-0033Front

Mathematics · IMC 2016Professor Pi

Perpendicular bisectors of each other

HintTwo lines through the centre; think about the symmetry of the shape.

The whyThe diagonals of a rhombus cross at right angles and each cuts the other in half, so they carve the shape into four congruent right-angled triangles. Two circles of equal radius that cross: their centres and crossing points form a rhombus, so the line of centres and the common chord bisect each other at right angles.

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KS3-MATH-IMC-0033Back

Mathematics · IMC 2016Professor Pi
↔ Asked both waysAnswer in your head…The overall speed of someone walking along a moving walkway
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KS3-MATH-IMC-0034Front

Mathematics · IMC 2016Professor Pi

Their own speed plus the walkway's speed

HintBoth motions carry the person forward at once.

The whySpeeds add, times do not: convert both to speeds (distance ÷ time), add, convert back.

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KS3-MATH-IMC-0034Back

Mathematics · IMC 2016Professor Pi
Answer in your head…Every length of a shape is multiplied by k. Its area is multiplied by…?
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KS3-MATH-IMC-0035Front

Mathematics · IMC 2016Professor Pi

HintLength counts once, area twice.

The whyDoubling every length quadruples the area — for a hexagon, a triangle, or any shape at all.

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KS3-MATH-IMC-0035Back

Mathematics · IMC 2016Professor Pi
Answer in your head…Two products are subtracted and one number appears in both, up to a power of ten. What is the fast route?
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KS3-MATH-IMC-0036Front

Mathematics · IMC 2016Professor Pi

Take out the common factor

HintShift a power of ten so both products share a piece, then factorise.

The whyNon-calculator papers plant these on purpose: multiplying out is slow and error-prone, but rewriting one number as the other times a power of ten turns the whole thing into (common factor) × (a simple subtraction). If a calculation looks brutal, look for what the two halves share.

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KS3-MATH-IMC-0036Back

IMC 2016

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