Every card in Number, Year 11: surds and recurring decimals
The whole deck, in order — so you can read it through before your child ever sees it.
- A root, such as √2 or √7, whose value cannot be written exactly as a whole number or a fraction, so it is left as a root
A surd
HintIt rhymes with 'word' and has four letters.
Why√2 = 1.41421… goes on for ever without repeating, so the only exact way to write it is √2. A root such as √9 is not one of these, because it equals 3 exactly.
- Simplify √75.
5√3
HintWhich square number divides exactly into the number under the root?
Why75 = 25 × 3 and 25 is a square number, so √75 = √25 × √3 = 5√3. Always look for the largest square factor so that the job is finished in one step.
- 3√5 can be written as the square root of one whole number, √n. What is n? (number only)
45
HintTo go back under the root sign, the 3 has to be squared first.
Why3 = √9, so 3√5 = √9 × √5 = √(9 × 5) = √45. This is simplifying run backwards, and it is useful for comparing the sizes of surds.
- To simplify a surd such as √50 in one step, write the number under the root as a product in which one factor is the largest possible ____ number.
square
HintThink of 4, 9, 16, 25, 36 …
Why50 = 25 × 2, so √50 = √25 × √2 = 5√2. This works because √(a × b) = √a × √b. Choosing a smaller factor of this kind still works, but the answer then needs simplifying again.
- Is √9 + √16 equal to √(9 + 16)? Work out both to decide.
No: √9 + √16 = 7, but √(9 + 16) = √25 = 5
HintEvaluate each side separately as ordinary numbers.
WhyRoots can be split over multiplication and division, √(ab) = √a × √b, but not over addition or subtraction. That is why √2 + √3 cannot be combined into √5 and has to be left as it is.
- Simplify √20 + √45.
5√5
HintSimplify each root first; then see whether they are like terms.
Why√20 = 2√5 and √45 = 3√5, so the sum is 2√5 + 3√5 = 5√5. Surds add like algebra terms: only matching roots can be collected.
- Expand and simplify (3 + √2)(3 − √2). (number only)
7
HintMultiply out all four products and watch what happens to the two middle ones.
Why9 − 3√2 + 3√2 − (√2)² = 9 − 2 = 7. The middle terms cancel and √2 × √2 = 2, so the surd disappears. This is the difference of two squares, 3² − (√2)².
- Rationalise the denominator of 6/√3. Give your answer in its simplest form.
2√3
HintMultiply the top and the bottom by the root that is on the bottom.
Why6/√3 × √3/√3 = 6√3/3 = 2√3. Multiplying top and bottom by √3 is multiplying by 1, so the value is unchanged, and √3 × √3 = 3 clears the root from the bottom.
- Rewriting a fraction such as 1/√2 as an equal fraction that has no surd on the bottom, here √2/2
Rationalising the denominator
HintThe name describes turning the bottom number into one that is not a surd.
WhyMultiply the top and the bottom by the surd on the bottom: 1/√2 × √2/√2 = √2/2. The value is the same; it is simply written in the agreed tidy form, which is easier to add to other fractions.
- Expand and simplify (2 + √3)².
7 + 4√3
HintWrite the bracket out twice and multiply every pair of terms.
Why(2 + √3)(2 + √3) = 4 + 2√3 + 2√3 + 3 = 7 + 4√3. The two middle terms are alike and add; the last term is √3 × √3 = 3.
- Write the recurring decimal 0.777… (the 7 repeats for ever) as a fraction. (type as a/b)
7/9
HintCall it x, then compare x with ten lots of x.
WhyLet x = 0.777…, so 10x = 7.777…. Subtracting, 9x = 7 and x = 7/9. The subtraction works because both numbers have exactly the same digits after the decimal point.
- To write x = 0.454545… as a fraction: multiply by ____ to shift one whole repeating block; subtract x to leave ____x = 45; so x, in its simplest form, is ____.
100; 99; 5/11
HintThe repeating block is two digits long.
Why100x = 45.454545… and x = 0.454545…, so subtracting gives 99x = 45. Then x = 45/99, and dividing top and bottom by 9 gives 5/11.
- Write 0.1666… (only the 6 repeats) as a fraction in its simplest form.
1/6
HintFind two multiples of x that have identical digits after the decimal point.
WhyLet x = 0.1666…. Then 10x = 1.666… and 100x = 16.666…, so 100x − 10x = 90x = 15. So x = 15/90 = 1/6.
- Put these in order, smallest first: 0.333… (the 3 repeats for ever), 0.33 and 3/10.
3/10, 0.33, 0.333…
HintWrite all three to four decimal places.
Why3/10 = 0.3000, 0.33 = 0.3300 and the recurring decimal is 0.3333…, which is 1/3. Comparing digit by digit gives the order.
- To turn x = 0.777… into a fraction you work out 10x − x. Why does this subtraction get rid of the recurring part?
10x and x have exactly the same digits after the decimal point, so those digits cancel
HintWrite the two numbers one above the other and look to the right of the dot.
Why10x = 7.777… and x = 0.777…. Everything to the right of the point matches, so the subtraction leaves a whole number: 9x = 7. Multiplying by the right power of ten is all about making the tails match.
1★ GCSE-MATH-NUM-0031
2★ GCSE-MATH-NUM-0032
3★ GCSE-MATH-NUM-0033
4★ GCSE-MATH-NUM-0034
5★ GCSE-MATH-NUM-0035
6★ GCSE-MATH-NUM-0036
7★ GCSE-MATH-NUM-0037
8★ GCSE-MATH-NUM-0038
9★ GCSE-MATH-NUM-0039
10★ GCSE-MATH-NUM-0040
11★ GCSE-MATH-NUM-0041
12★ GCSE-MATH-NUM-0042
13★ GCSE-MATH-NUM-0043
14★ GCSE-MATH-NUM-0044
15★ GCSE-MATH-NUM-0045
Keep what you learn
Here, nothing is saved. In your child’s own sky every card is scheduled — it comes back just before they’d forget it — and the professor who wrote it is one tap away.