Mathematics

Number, Year 11: surds and recurring decimals

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MathematicsNumber, Year 11: surds and recurring decimals
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Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
↔ Asked both waysAnswer in your head…A root, such as √2 or √7, whose value cannot be written exactly as a whole number or a fraction, so it is left as a root
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★ GCSE-MATH-NUM-0031Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

A surd

HintIt rhymes with 'word' and has four letters.

The why√2 = 1.41421… goes on for ever without repeating, so the only exact way to write it is √2. A root such as √9 is not one of these, because it equals 3 exactly.

★ GCSE-MATH-NUM-0031Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Simplify √75.
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★ GCSE-MATH-NUM-0032Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

5√3

HintWhich square number divides exactly into the number under the root?

The why75 = 25 × 3 and 25 is a square number, so √75 = √25 × √3 = 5√3. Always look for the largest square factor so that the job is finished in one step.

★ GCSE-MATH-NUM-0032Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
⌨ Type the answerAnswer in your head…3√5 can be written as the square root of one whole number, √n. What is n? (number only)

★ GCSE-MATH-NUM-0033Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

45

HintTo go back under the root sign, the 3 has to be squared first.

The why3 = √9, so 3√5 = √9 × √5 = √(9 × 5) = √45. This is simplifying run backwards, and it is useful for comparing the sizes of surds.

★ GCSE-MATH-NUM-0033Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Fill the gapAnswer in your head…To simplify a surd such as √50 in one step, write the number under the root as a product in which one factor is the largest possible ____ number.
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★ GCSE-MATH-NUM-0034Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

square

HintThink of 4, 9, 16, 25, 36 …

The why50 = 25 × 2, so √50 = √25 × √2 = 5√2. This works because √(a × b) = √a × √b. Choosing a smaller factor of this kind still works, but the answer then needs simplifying again.

★ GCSE-MATH-NUM-0034Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Is √9 + √16 equal to √(9 + 16)? Work out both to decide.
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★ GCSE-MATH-NUM-0035Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

No: √9 + √16 = 7, but √(9 + 16) = √25 = 5

HintEvaluate each side separately as ordinary numbers.

The whyRoots can be split over multiplication and division, √(ab) = √a × √b, but not over addition or subtraction. That is why √2 + √3 cannot be combined into √5 and has to be left as it is.

★ GCSE-MATH-NUM-0035Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Simplify √20 + √45.
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★ GCSE-MATH-NUM-0036Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

5√5

HintSimplify each root first; then see whether they are like terms.

The why√20 = 2√5 and √45 = 3√5, so the sum is 2√5 + 3√5 = 5√5. Surds add like algebra terms: only matching roots can be collected.

★ GCSE-MATH-NUM-0036Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
⌨ Type the answerAnswer in your head…Expand and simplify (3 + √2)(3 − √2). (number only)

★ GCSE-MATH-NUM-0037Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

7

HintMultiply out all four products and watch what happens to the two middle ones.

The why9 − 3√2 + 3√2 − (√2)² = 9 − 2 = 7. The middle terms cancel and √2 × √2 = 2, so the surd disappears. This is the difference of two squares, 3² − (√2)².

★ GCSE-MATH-NUM-0037Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Rationalise the denominator of 6/√3. Give your answer in its simplest form.
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★ GCSE-MATH-NUM-0038Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

2√3

HintMultiply the top and the bottom by the root that is on the bottom.

The why6/√3 × √3/√3 = 6√3/3 = 2√3. Multiplying top and bottom by √3 is multiplying by 1, so the value is unchanged, and √3 × √3 = 3 clears the root from the bottom.

★ GCSE-MATH-NUM-0038Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
↔ Asked both waysAnswer in your head…Rewriting a fraction such as 1/√2 as an equal fraction that has no surd on the bottom, here √2/2
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★ GCSE-MATH-NUM-0039Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

Rationalising the denominator

HintThe name describes turning the bottom number into one that is not a surd.

The whyMultiply the top and the bottom by the surd on the bottom: 1/√2 × √2/√2 = √2/2. The value is the same; it is simply written in the agreed tidy form, which is easier to add to other fractions.

★ GCSE-MATH-NUM-0039Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Expand and simplify (2 + √3)².
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★ GCSE-MATH-NUM-0040Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

7 + 4√3

HintWrite the bracket out twice and multiply every pair of terms.

The why(2 + √3)(2 + √3) = 4 + 2√3 + 2√3 + 3 = 7 + 4√3. The two middle terms are alike and add; the last term is √3 × √3 = 3.

★ GCSE-MATH-NUM-0040Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
⌨ Type the answerAnswer in your head…Write the recurring decimal 0.777… (the 7 repeats for ever) as a fraction. (type as a/b)

★ GCSE-MATH-NUM-0041Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

7/9

HintCall it x, then compare x with ten lots of x.

The whyLet x = 0.777…, so 10x = 7.777…. Subtracting, 9x = 7 and x = 7/9. The subtraction works because both numbers have exactly the same digits after the decimal point.

★ GCSE-MATH-NUM-0041Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Fill the gapsAnswer in your head…To write x = 0.454545… as a fraction: multiply by ____ to shift one whole repeating block; subtract x to leave ____x = 45; so x, in its simplest form, is ____.
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★ GCSE-MATH-NUM-0042Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

100; 99; 5/11

HintThe repeating block is two digits long.

The why100x = 45.454545… and x = 0.454545…, so subtracting gives 99x = 45. Then x = 45/99, and dividing top and bottom by 9 gives 5/11.

★ GCSE-MATH-NUM-0042Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Write 0.1666… (only the 6 repeats) as a fraction in its simplest form.
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★ GCSE-MATH-NUM-0043Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

1/6

HintFind two multiples of x that have identical digits after the decimal point.

The whyLet x = 0.1666…. Then 10x = 1.666… and 100x = 16.666…, so 100x − 10x = 90x = 15. So x = 15/90 = 1/6.

★ GCSE-MATH-NUM-0043Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…Put these in order, smallest first: 0.333… (the 3 repeats for ever), 0.33 and 3/10.
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★ GCSE-MATH-NUM-0044Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

3/10, 0.33, 0.333…

HintWrite all three to four decimal places.

The why3/10 = 0.3000, 0.33 = 0.3300 and the recurring decimal is 0.3333…, which is 1/3. Comparing digit by digit gives the order.

★ GCSE-MATH-NUM-0044Back

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi
Answer in your head…To turn x = 0.777… into a fraction you work out 10x − x. Why does this subtraction get rid of the recurring part?
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★ GCSE-MATH-NUM-0045Front

Mathematics · Number, Year 11: surds and recurring decimalsProfessor Pi

10x and x have exactly the same digits after the decimal point, so those digits cancel

HintWrite the two numbers one above the other and look to the right of the dot.

The why10x = 7.777… and x = 0.777…. Everything to the right of the point matches, so the subtraction leaves a whole number: 9x = 7. Multiplying by the right power of ten is all about making the tails match.

★ GCSE-MATH-NUM-0045Back

Number, Year 11: surds and recurring decimals

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