Mathematics

JMC 2015

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MathematicsJMC 2015
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Mathematics · JMC 2015Professor Pi
Answer in your head…Walk once around any polygon, turning at every corner. The turns you make — the exterior angles — always add up to how much?
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KS3-MATH-JMC-0013Front

Mathematics · JMC 2015Professor Pi

360°

HintOne full circuit brings you back facing the way you started.

The whyThis is true for a triangle, a hexagon or a fifty-sided shape: the exterior angles sum to 360° whatever the number of sides. It is often quicker than the interior-angle formula — find the missing exterior angle first, then use the straight line (180°) to reach the interior angle beside it.

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Mathematics · JMC 2015Professor Pi
↔ Asked both waysAnswer in your head…The exterior angle theorem for a triangle
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Mathematics · JMC 2015Professor Pi

Exterior angle = sum of the two opposite interior angles

HintExtend one side past a corner: the turn made there matches the pair of corners far away.

The whyIt follows from two facts you already know: the angles of a triangle add to 180°, and the angles on a straight line add to 180°. Competition setters love it because it lets you leap straight to an answer without finding every angle in the diagram.

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Mathematics · JMC 2015Professor Pi
Answer in your head…For two positive whole numbers, adding them usually gives less than multiplying them. When does adding give MORE?
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KS3-MATH-JMC-0015Front

Mathematics · JMC 2015Professor Pi

When either is 1

HintTry a few pairs where one number is tiny.

The why1 + 7 = 8 but 1 × 7 = 7, so a 1 is the one case where the plus sign wins. With 2 and 2 the two results are equal (4 and 4); from 2 and 3 upwards, multiplying is always bigger. So when you may choose + or × to make an expression as large as possible, multiply everything — except that a 1 should be added, not multiplied.

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Mathematics · JMC 2015Professor Pi
⌨ Type the answerAnswer in your head…Which number is the only even prime? (type the number only)

KS3-MATH-JMC-0016Front

Mathematics · JMC 2015Professor Pi

2

HintEvery other even number has this number as a factor, so it cannot be prime itself.

The whyBecause 2 is the only even prime, every other prime is odd. That drives a family of parity arguments: odd + odd is even, so the sum of two odd primes can never be prime, and any question about sums of primes usually turns on whether a 2 is involved.

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Mathematics · JMC 2015Professor Pi
Fill the gapAnswer in your head…The smallest number that every whole number from 1 to 10 divides into exactly is ____.
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Mathematics · JMC 2015Professor Pi

2520

HintNot 10 factorial — that repeats factors. One highest power per prime.

The why2520 = 8 × 9 × 5 × 7. Any number divisible by everything from 1 to 10 must be a multiple of 2520, so the fast check is: does it have three 2s, two 3s, a 5 and a 7 among its prime factors? Being divisible by 5 needs a last digit of 0 or 5, which alone eliminates most options.

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Mathematics · JMC 2015Professor Pi
Fill the gapsAnswer in your head…Each angle of an equilateral triangle is ____°, each angle of a square is ____° and each interior angle of a regular hexagon is ____°.
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KS3-MATH-JMC-0018Front

Mathematics · JMC 2015Professor Pi

60; 90; 120

HintThe three shapes that tile a flat floor on their own: think how many meet at a point.

The whyThese three appear together constantly: a square sitting on a triangle, a hexagon with a square on one side. Whenever shapes meet at a point, add the known corners and subtract from 360° to find the gap; whenever they meet along a line, subtract from 180°.

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Mathematics · JMC 2015Professor Pi
Answer in your head…You need only the final digit of a long multiplication such as 4837 × 2596. Which digits of the two numbers actually matter?
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KS3-MATH-JMC-0019Front

Mathematics · JMC 2015Professor Pi

Only their units digits

HintThink about what the last column of the working depends on.

The whyThe last digit of a product depends only on the last digits of the factors: 7 × 6 = 42, so 4837 × 2596 ends in 2. Two products with different final digits cannot be equal, which lets you reject answer options without doing any long multiplication.

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Mathematics · JMC 2015Professor Pi
Answer in your head…Some tiles overlap inside a frame. You know the area of each tile and the area of the frame they cover between them. How do you find the total area of overlap?
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KS3-MATH-JMC-0020Front

Mathematics · JMC 2015Professor Pi

Total of areas − area covered

HintWhere two tiles sit on the same spot, that spot has been counted twice.

The whyAdding the tiles' areas counts every overlapping patch once per tile, while the covered region counts it once. The difference is exactly the overlap (as long as no spot is covered three times over). It is the same idea as a Venn diagram: add the parts, then take away what was counted twice.

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Mathematics · JMC 2015Professor Pi
↔ Asked both waysAnswer in your head…A palindromic number
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KS3-MATH-JMC-0021Front

Mathematics · JMC 2015Professor Pi

A number that reads the same forwards and backwards

HintLike the words noon and level, but made of digits.

The whySuch a number can never end in 0, because it would then have to begin with 0. So whatever a last-digit test tells you about the units digit — even, or a multiple of 5 — it tells you about the leading digit as well, before you have done any arithmetic.

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Mathematics · JMC 2015Professor Pi
⌨ Type the answerAnswer in your head…How many of the ten digits 0 to 9 are prime numbers? (type the number only)

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Mathematics · JMC 2015Professor Pi

4

HintNeither 0 nor 1 is prime, and every even digit but one is out.

The whyThe prime digits are 2, 3, 5 and 7. Knowing them by heart speeds up any question about primes built from digits.

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Mathematics · JMC 2015Professor Pi
Fill the gapAnswer in your head…Joining the centre of a regular hexagon to every vertex cuts it into six identical ____ triangles.
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KS3-MATH-JMC-0023Front

Mathematics · JMC 2015Professor Pi

equilateral

HintThe angle at the centre is a sixth of a full turn, and two sides of each piece are the same length.

The whyEach central angle is 360° ÷ 6 = 60°, and the two sides from the centre are equal, so every piece is an equilateral triangle with the hexagon's own side length. Shaded-fraction questions on hexagons are usually solved by counting these six triangles — or the twenty-four smaller ones you get by quartering each.

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KS3-MATH-JMC-0023Back

Mathematics · JMC 2015Professor Pi
Answer in your head…In a number pyramid every brick is the sum of the two bricks directly beneath it. A brick in a lower row is missing, but the brick above it and its neighbour are known. What do you do?
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KS3-MATH-JMC-0024Front

Mathematics · JMC 2015Professor Pi

Brick above minus neighbour

HintSums going up mean the reverse operation coming down.

The whyWorking downwards is the inverse of working upwards, so every step down is a subtraction. Fill in only the bricks you actually need: a missing bottom corner often needs just a diagonal chain of subtractions, not the whole pyramid.

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JMC 2015

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