Mathematics

IMC 2021

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MathematicsIMC 2021
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Mathematics · IMC 2021Professor Pi
Answer in your head…A polygon's corner points inwards. Which angle does the 180(n − 2) angle sum use there?
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★ KS3-MATH-IMC-0085Front

Mathematics · IMC 2021Professor Pi

The reflex interior angle

HintMore than a half turn, measured on the inside.

The whyThe formula counts the angle on the inside of the shape at every vertex; where the boundary turns inward, that inside angle is bigger than 180°. At a square's corner seen from outside, the inside angle of the surrounding polygon is 360° − 90°.

★ KS3-MATH-IMC-0085Back

Mathematics · IMC 2021Professor Pi
Fill the gapAnswer in your head…A number and its digit sum leave the ____ remainder on division by 9.
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★ KS3-MATH-IMC-0086Front

Mathematics · IMC 2021Professor Pi

same

Hint10, 100, 1000 … each leave remainder 1.

The whyBecause 10, 100, 1000 … are all 1 more than a multiple of 9, a number and its digit sum differ by a multiple of 9 — so they share a remainder, and the same is true for division by 3. It also drives 'casting out nines': the remainder of a product by 9 comes from the remainders of its factors.

★ KS3-MATH-IMC-0086Back

Mathematics · IMC 2021Professor Pi
Answer in your head…The product of several whole numbers is odd. What can you say for certain about every one of the factors?
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★ KS3-MATH-IMC-0087Front

Mathematics · IMC 2021Professor Pi

Each factor is odd

HintOne even number in the mix is enough to change everything.

The whyA single even factor drags a 2 into the product and makes it even, so an odd product rules every even factor out. That is the contrapositive of the familiar rule, and it is the direction competition questions actually use — 3 × 5 × 7 stays odd, but 3 × 4 × 5 cannot.

★ KS3-MATH-IMC-0087Back

Mathematics · IMC 2021Professor Pi
↔ Asked both waysAnswer in your head…The transformation sending (x, y) to (x, −y)
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★ KS3-MATH-IMC-0088Front

Mathematics · IMC 2021Professor Pi

Reflection in the x-axis

HintThe first coordinate is untouched, so the mirror runs along that direction.

The whyReflect in the x-axis: y changes sign. Reflect in the y-axis: x changes sign. Reflect in y = x: swap the coordinates. Applied to a whole line, y = 3x − 5 becomes −y = 3x − 5, that is y = −3x + 5: the gradient and the intercept both flip sign.

★ KS3-MATH-IMC-0088Back

Mathematics · IMC 2021Professor Pi
⌨ Type the answerAnswer in your head…The area of a semicircle of radius r is πr² divided by…? (type the number only)

★ KS3-MATH-IMC-0089Front

Mathematics · IMC 2021Professor Pi

2

HintIt is a fraction of the full disc.

The whyA semicircle of diameter 10 has area 12.5π; a quarter circle of radius 4 has area 4π. Leave π in the answer — the options are written with it.

★ KS3-MATH-IMC-0089Back

Mathematics · IMC 2021Professor Pi
⌨ Type the answerAnswer in your head…Shorter sides in the ratio 3 : 4. Without Pythagoras, the hypotenuse completes the ratio with…? (type the number only)

★ KS3-MATH-IMC-0090Front

Mathematics · IMC 2021Professor Pi

5

HintThe most famous whole-number right-angled triangle.

The whyMultiples of 3-4-5 (6-8-10, 9-12-15, 15-20-25) and of 5-12-13 (10-24-26) appear constantly, often hidden inside a diagram. Spot the triple and the square root is never needed.

★ KS3-MATH-IMC-0090Back

Mathematics · IMC 2021Professor Pi
Answer in your head…Two circles of radius 6 overlap. The region they cover altogether has area 60π. What is the area of the overlap, in terms of π?
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★ KS3-MATH-IMC-0091Front

Mathematics · IMC 2021Professor Pi

12π

HintWork out what each circle would cover on its own, then compare.

The whyInclusion–exclusion runs backwards just as well: covered = first + second − overlap. Each circle has area π × 6² = 36π, so on their own they account for 72π; the covered region is only 60π, and the missing 12π is exactly the piece that was counted twice. The same rearrangement finds the overlap of any two regions once the total covered area is known.

★ KS3-MATH-IMC-0091Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A question says two lines meet at a given point and asks for an unknown constant in their equations. What is the first move?
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★ KS3-MATH-IMC-0092Front

Mathematics · IMC 2021Professor Pi

Substitute the point into both equations

HintWhat is true of any position that lies on a line?

The whyA point on a line makes the line's equation true. So a shared point gives one true equation per line — two lines, two equations — which is usually exactly enough to pin down two unknown constants.

★ KS3-MATH-IMC-0092Back

Mathematics · IMC 2021Professor Pi
↔ Asked both waysAnswer in your head…The formula distance ÷ time
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★ KS3-MATH-IMC-0093Front

Mathematics · IMC 2021Professor Pi

Average speed

HintIt is a rate, not a length or a time.

The whyKeep the units consistent before anything else: a 'three minutes less' clue needs the hours converted to minutes (or 3 minutes written as 1/20 of an hour).

★ KS3-MATH-IMC-0093Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A question fixes the mean and asks how many numbers were added. Which equation do you write?
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★ KS3-MATH-IMC-0094Front

Mathematics · IMC 2021Professor Pi

total = mean × count

HintWork with the sum of everything, not the average itself.

The whyLet the unknown count appear on both sides: the added numbers raise the total and the count at once, and the fixed mean ties them together in one equation.

★ KS3-MATH-IMC-0094Back

Mathematics · IMC 2021Professor Pi
Fill the gapsAnswer in your head…Subtracting a negative is the same as ____, and a negative times a negative is ____.
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★ KS3-MATH-IMC-0095Front

Mathematics · IMC 2021Professor Pi

adding; positive

HintTwo minus signs together.

The why2 − (−3) = 5 and (−2) × (−3) = 6, but −2 − 3 = −5 and (−2) + (−3) = −5: only two signs that act on each other cancel. Work nested brackets from the inside out.

★ KS3-MATH-IMC-0095Back

Mathematics · IMC 2021Professor Pi
Fill the gapAnswer in your head…Dividing by a fraction is the same as multiplying by its ____.
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★ KS3-MATH-IMC-0096Front

Mathematics · IMC 2021Professor Pi

reciprocal

HintHow many quarters fit into 3?

The why3 ÷ ¼ = 3 × 4 = 12: dividing by a small fraction gives a big answer. Turn mixed numbers into improper fractions before you flip anything.

★ KS3-MATH-IMC-0096Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A calculation like a − b + c has only + and − between its numbers, no brackets. In what order may the terms be combined?
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★ KS3-MATH-IMC-0241Front

Mathematics · IMC 2021Professor Pi

Any order — each number just keeps the sign glued to it

HintRegroup the terms that combine nicely; the + or − in front of a term travels with it.

The whyFor example, 8 − 3 + 5 can be rearranged to 8 + 5 − 3, always giving 10 — grouping the positives and negatives separately before combining once often saves work, especially with larger or messier numbers.

★ KS3-MATH-IMC-0241Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A word problem strings together phrases like 'the day before yesterday' or 'two days after'. What is the reliable way to work out which day is meant?
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★ KS3-MATH-IMC-0242Front

Mathematics · IMC 2021Professor Pi

Convert each clue into a day-offset, then count from a known day

HintGive every phrase a plus or minus shift in days, and add them up starting at something certain.

The whyTreat 'today' as day 0. 'Yesterday' is −1, 'the day before X' is (X − 1), and 'two days after Y' is (Y + 2). Chain the offsets together in the order the sentence gives them, then convert the final number back into a day of the week.

★ KS3-MATH-IMC-0242Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A problem gives three related but unknown quantities, each described as a fraction or ratio of another, and states their total. What is the standard approach?
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★ KS3-MATH-IMC-0243Front

Mathematics · IMC 2021Professor Pi

Let one quantity be x, express the rest in terms of x, then solve

HintPick one unknown as the anchor, and rewrite the other amounts using that same letter.

The whyIf B is three-fifths of C, and A is half of B, write everything in terms of C: B = (3/5)C and A = (1/2)(3/5)C = (3/10)C. Adding A + B + C to the known total gives one equation in one unknown, which can then be solved directly.

★ KS3-MATH-IMC-0243Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A problem asks for positive integers that are NOT factors of a given number, in ascending order. What is the most reliable first step?
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★ KS3-MATH-IMC-0244Front

Mathematics · IMC 2021Professor Pi

First find all the factors of that number, in order

HintWork out the complete set of divisors before you go hunting for what's missing.

The whyNumbers not in that list are simply everything else, counted off in order — e.g. if the factors of 20 up to 20 are 1, 2, 4, 5, 10, 20, the non-factors below 20 are 3, 6, 7, 8, 9, and so on, continuing past whichever factors come next as you climb higher.

★ KS3-MATH-IMC-0244Back

Mathematics · IMC 2021Professor Pi
↔ Asked both waysAnswer in your head…The expanded form of (a + k)(b + k), written in terms of ab, k and (a + b)
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★ KS3-MATH-IMC-0245Front

Mathematics · IMC 2021Professor Pi

ab + k(a + b) + k²

HintMultiply out two brackets that share the same added constant.

The whyThis turns an unfamiliar product into a known one. If 24 × 28 = 672 is already known, adding 6 to each factor gives 30 × 34 = 672 + 6 × (24 + 28) + 36 = 1020 — much quicker than multiplying two large numbers from scratch.

★ KS3-MATH-IMC-0245Back

Mathematics · IMC 2021Professor Pi
⌨ Type the answerAnswer in your head…25% of 60% of a number equals what single percentage of that number? (type the number only)

★ KS3-MATH-IMC-0246Front

Mathematics · IMC 2021Professor Pi

15

HintMultiply the two percentages' decimal forms together, then convert back to a percentage.

The whyPercentages of percentages combine by multiplication, not addition: 0.25 × 0.60 = 0.15, so 25% of 60% of a number is 15% of it — not 85% (25+60) and not 35% (60−25). The same idea extends to any chain: three consecutive percentage operations multiply three decimals together.

★ KS3-MATH-IMC-0246Back

Mathematics · IMC 2021Professor Pi
Answer in your head…A shaded-area diagram gives no actual lengths, only a grid of same-sized smaller squares. What is a useful first step before calculating the shaded fraction?
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★ KS3-MATH-IMC-0247Front

Mathematics · IMC 2021Professor Pi

Assign the smallest square a convenient length, such as 1

HintGive the tiniest repeating unit an easy value so every area works out as a whole number.

The whyIf the smallest squares in the diagram have side-length 1, every other length and area in the figure becomes a whole number instead of an unknown ratio — turn the shaded area into a fraction of the total, then convert that fraction to a percentage.

★ KS3-MATH-IMC-0247Back

Mathematics · IMC 2021Professor Pi
↔ Asked both waysAnswer in your head…The altitude from the apex of an isosceles triangle to its base
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★ KS3-MATH-IMC-0248Front

Mathematics · IMC 2021Professor Pi

Bisects the base and meets it at right angles

HintSymmetry splits the triangle into two identical mirror-image halves.

The whyThis works because reflecting the triangle in that altitude maps the shape onto itself, swapping the two base vertices — so the altitude must land exactly at the base's midpoint, and Pythagoras' Theorem then applies directly in either half using half the base and the equal side.

★ KS3-MATH-IMC-0248Back

Mathematics · IMC 2021Professor Pi
Answer in your head…Two recurring decimals look almost identical to one another when you glance at only the first couple of digits. What should you do to compare them accurately against a whole number?
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★ KS3-MATH-IMC-0249Front

Mathematics · IMC 2021Professor Pi

Expand several repeats of each recurring block first

HintWrite out enough copies of the repeating pattern to see clearly which side of the target number you land on, and by how much.

The whyRecurring decimals hide their real size in the first few digits, so extend the pattern before judging which side of a target number they fall on — a value like 0.161616… can look bigger than 0.162 at a glance, but writing out several repeats (0.16161616…) shows the true value is smaller.

★ KS3-MATH-IMC-0249Back

Mathematics · IMC 2021Professor Pi
Answer in your head…Two similar shapes have side lengths in ratio a : b. What is the ratio of their areas?
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★ KS3-MATH-IMC-0250Front

Mathematics · IMC 2021Professor Pi

a² : b²

HintArea scales with the square of the length scale factor, not the factor itself.

The whySimilar shapes multiply every length by the same scale factor k, but area — being length × length — scales by k². A shape enlarged by scale factor 3 has 9 times the area, not 3 times, and a similar solid’s volume would scale by k³.

★ KS3-MATH-IMC-0250Back

Mathematics · IMC 2021Professor Pi
Answer in your head…An expression multiplies several terms, each of the form 1 plus or minus a fraction. What is the most efficient first step?
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★ KS3-MATH-IMC-0251Front

Mathematics · IMC 2021Professor Pi

Rewrite each term as one single fraction

HintFind a common denominator inside every set of brackets before multiplying across.

The why1 + 2/x becomes (x + 2)/x once written over a common denominator; do this to every factor first, and terms often cancel across the brackets, leaving a far simpler result than multiplying everything out piece by piece.

★ KS3-MATH-IMC-0251Back

Mathematics · IMC 2021Professor Pi
Fill the gapAnswer in your head…7n is a multiple of 4. Since 7 and 4 are ____, n itself must be a multiple of 4.
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★ KS3-MATH-IMC-0252Front

Mathematics · IMC 2021Professor Pi

coprime

Hint7 and 4 have no common factor other than 1.

The whyThis is a general rule: if a × n is a multiple of b, and a and b share no common factor, then n itself must be a multiple of b — because none of b's prime factors can come from a, so they all have to come from n. The same idea shows a fraction is already in lowest terms when top and bottom share no factor.

★ KS3-MATH-IMC-0252Back

Mathematics · IMC 2021Professor Pi
Answer in your head…Someone's speed over a moving walkway or escalator equals their own speed on solid ground plus what?
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★ KS3-MATH-IMC-0253Front

Mathematics · IMC 2021Professor Pi

The walkway's speed (in the direction of travel)

HintThe moving surface itself contributes extra distance covered per second.

The whySet up one equation per scenario using distance = speed × time: for the walkway moving, running speed + walkway speed = distance/time; for the stationary walkway, running speed alone = distance/time. Subtracting the equations isolates the walkway’s own speed, and the same idea gives walking speed too.

★ KS3-MATH-IMC-0253Back

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