Every card in IMC 2019
The whole deck, in order — so you can read it through before your child ever sees it.
- Two unit cubes are glued together face to face. By how much does their combined surface area fall?
By two faces
HintNothing is added; something is hidden — on both sides.
WhyEvery join hides one face from each cube, so a shape built from k cubes with j face-to-face joins has surface area 6k − 2j. The shape with the most joins has the smallest surface area — count joins, not exposed faces.
- What decides the units digit of n³?
The units digit of n
HintCube 12 and 22 and compare the endings.
WhyThe same is true of every power, so a cube ends in 8 only when the number cubed ends in 2, and a square ends in 9 only when its root ends in 3 or 7. Unlike squares, cubes can end in any digit — each of 0 to 9 appears exactly once among the cubes of 0 to 9.
- The sequence 1, 3, 6, 10, 15, 21, …
The triangular numbers
Hint1, then 1 + 2, then 1 + 2 + 3 …
WhyThe nth triangular number is n(n + 1)/2 — the sum of the whole numbers from 1 to n. They run odd, odd, even, even, so a triangular number just after an even number is odd.
- When multiplying or dividing, two numbers with the same sign give a ____ answer, two with different signs give a ____ answer, and anything times zero gives zero.
positive; negative
HintSame signs, different signs, and the one number that swallows everything.
WhyThe sign rules apply to × and ÷ only — adding two negatives gives a negative, and subtracting a negative is adding. Order-of-operations questions packed with brackets and minus signs are testing whether you apply each rule to the right operation.
- One billion is ten to the power of what? (type the number only)
9
HintA thousand millions: add the zeros.
WhyA billion has nine zeros. Dividing it by a smaller round number is best done by cancelling powers of ten first — 10⁹ ÷ (4 × 10⁴) = 10⁵ ÷ 4 = 25 000 — so the zeros are never miscounted.
- (aᵐ)ⁿ = aᵐⁿ: a power of a power ____ the indices.
multiplies
HintWrite (a²)³ out in full and look at how many a's you get.
WhyCompare 8⁵ with 4⁷ by writing both as powers of 2: 2¹⁵ against 2¹⁴. Keeping everything as a power of the smallest base is the whole technique for index questions with no calculator.
- A token moves one square at a time on a chessboard. Which strategy tells you at once which squares it could be on after an odd number of moves?
Watch the square's colour
HintEvery single move flips something that only has two states.
WhyColour the board like a chessboard: every move — a step to a neighbour, or a reflection in a line running between rows or columns — swaps black for white. After an odd number of moves the token is on the opposite colour to where it started; after an even number, the same colour. Parity halves the search before you list anything.
- An equation has the unknown x in two terms, one on each side. After collecting them on one side, what is the key move to make x the subject?
Factorise x out
HintBoth terms contain x — what does that let you write?
WhyFrom ab = 2a + b: a(b − 2) = b, so a = b ÷ (b − 2); check that b = 2 is impossible in the original before dividing by the bracket.
- 0.7 recurring, written as a fraction, is ____.
7/9
HintNot tenths — the denominator that makes one digit repeat forever.
WhyA single recurring digit d is d/9; a recurring pair ab is ab/99. Add recurring decimals as fractions — the digit-by-digit method has no right-hand end to start from.
- Similar shapes: to turn an area ratio into a length ratio you…?
Take the square root
HintAreas came from lengths by one operation; go back the other way.
WhyAreas of similar shapes are in the ratio of the squares of their sides, so going from areas back to sides means taking a square root: areas 1 : 7 means sides 1 : √7 — not 1 : 3.5.
- 1001 = 7 × 11 × ? (type the missing prime only)
13
HintThree consecutive odd primes.
WhySo 123 123, 987 987 — any block-repeated six-digit number — is divisible by 7, 11 and 13, because it equals the block × 1001.
- Three lengths are given. When can they form a triangle?
Longest side < sum of the other two
HintTry 2, 3 and 10 with real sticks.
WhyThe triangle inequality — and every length must be positive. When side lengths are given as expressions in n, solving "two sides equal" is only half the job: each solution must then be checked against both conditions, and any that fails is discarded.
1★ KS3-MATH-IMC-0061
2★ KS3-MATH-IMC-0062
3★ KS3-MATH-IMC-0063
4★ KS3-MATH-IMC-0064
5★ KS3-MATH-IMC-0065
6★ KS3-MATH-IMC-0066
7★ KS3-MATH-IMC-0067
8★ KS3-MATH-IMC-0068
9★ KS3-MATH-IMC-0069
10★ KS3-MATH-IMC-0070
11★ KS3-MATH-IMC-0071
12★ KS3-MATH-IMC-0072
Keep what you learn
Here, nothing is saved. In your child’s own sky every card is scheduled — it comes back just before they’d forget it — and the professor who wrote it is one tap away.