Mathematics · Professor Pi

Number, Year 9: percentages, prime factors and methods:全部卡片

整套按顺序列出——孩子看到之前,您可以先通读一遍。

1 KS3-MATH-NUM-0029

After a 20% reduction, a pair of trainers costs £48. What was the price before the sale, in pounds? (number only)

60

提示The sale price is not the whole of the old price; decide what percentage of it you have been given.

为什么£48 is 80% of the original, so 10% is £6 and 100% is £60. Check forwards: 20% of £60 is £12, and £60 − £12 = £48.

2 KS3-MATH-NUM-0030

A jacket is reduced by 10% to £90. Sam adds 10% of £90 back on and gets £99. Why is that not the original price?

The 10% was taken off the original price, not off £90

提示Ask which amount each of the two percentages is a share of.

为什么The original was £100: 10% of £100 is £10, leaving £90. But 10% of £90 is only £9, so adding it back falls £1 short. A percentage always belongs to the amount it was worked out from.

3 KS3-MATH-NUM-0031

After a 25% pay rise, Asha earns £15 an hour. That £15 is ____% of her old hourly pay, so her old pay was £____ an hour.

125% and £12

提示A rise keeps all of what was there before and adds some more on top.

为什么100% + 25% = 125%, so £15 ÷ 1.25 gives the old pay. Check forwards: 25% of £12 is £3, and £12 + £3 = £15.

4 KS3-MATH-NUM-0032

A 15% deposit on a car comes to £1200. What is the full price of the car?

£8000

提示Scale the deposit down to a small, convenient percentage first, then build up to the whole.

为什么15% is £1200, so 5% is £400 and 100% is 20 × £400. Whenever you know what a percentage of an amount is worth, you can scale to 100% to recover the original.

5 KS3-MATH-NUM-0033

Mia works out that a tent cost £50 before a 30% discount brought it down to £35. How can she check her answer?

Take 30% off £50 and see whether it gives £35

提示Run the story forwards again, starting from the price she found.

为什么30% of £50 is £15, and £50 − £15 = £35, so she is right. Running the change forwards is the quickest way to catch the common mistake of adding the percentage back on to the sale price.

6 KS3-MATH-NUM-0034

72 = 2³ × 3² and 60 = 2² × 3 × 5. Use these prime factorisations to find the highest common factor of 72 and 60. (number only)

12

提示Keep only the primes found in both lists, each as many times as both can supply.

为什么Both numbers contain two 2s and one 3, so the HCF is 2 × 2 × 3. The third 2, the second 3 and the 5 are each missing from one of the numbers, so they cannot be part of a common factor.

7 KS3-MATH-NUM-0035

36 = 2² × 3² and 48 = 2⁴ × 3. Use these prime factorisations to find the lowest common multiple of 36 and 48.

144

提示Each prime must appear often enough to cover whichever of the two numbers needs it most.

为什么A common multiple must contain all of 36 and all of 48, so it needs four 2s (for 48) and two 3s (for 36): 16 × 9. With any fewer, one of the numbers would not divide into it.

8 KS3-MATH-NUM-0036

The prime factors of two numbers are sorted into a Venn diagram of two circles. The left-only region holds 5, the overlap holds 2, 2 and 3, and the right-only region holds 7. What are the two numbers?

60 and 84

提示Each number owns its own region together with the shared middle.

为什么The left circle holds 5 × 2 × 2 × 3 = 60 and the right circle holds 2 × 2 × 3 × 7 = 84. The overlap alone gives the HCF, 12, and every prime in the diagram multiplied together gives the LCM, 420.

9 KS3-MATH-NUM-0037

In a Venn diagram of the prime factors of two numbers, multiplying together every prime in the whole diagram gives their ____.

lowest common multiple

提示Everything in each circle is present, so each of the two numbers divides into the result.

为什么The whole diagram contains every prime of the first number and every prime of the second, with the shared ones counted once. That is exactly enough for both numbers to divide into it, and no more.

10 KS3-MATH-NUM-0038

Why does the highest common factor of two numbers use only the prime factors that appear in both?

A common factor has to divide into both numbers

提示Think what would go wrong if you included a 5 when only one of them contains a 5.

为什么A prime that is missing from one number cannot be part of anything that divides it. So the HCF is built only from shared primes, while the LCM, which both numbers must divide into, needs every prime that either number has.

11 KS3-MATH-NUM-0039

Work out 25 × 36 in your head. (number only)

900

提示Twenty-five is a quarter of a hundred.

为什么36 ÷ 4 = 9, and 9 × 100 = 900. Spotting that 25 is a quarter of 100 turns a long multiplication into two easy steps, quicker and safer than reaching for a calculator.

12 KS3-MATH-NUM-0040

Estimate 4.87 × 21.3 by rounding each number to one significant figure.

5 × 20 = 100

提示Round each to its leading digit before multiplying.

为什么The exact answer is 103.731, so the estimate is close enough to catch a misplaced decimal point or a wrong key press. An estimate run alongside a calculation costs a few seconds.

13 KS3-MATH-NUM-0041

A calculator display shows 3.2 × 48 = 1536. Without working it out exactly, how do you know the display is wrong?

3 × 50 is about 150, so 1536 is ten times too big

提示Round each value to something easy and multiply those.

为什么3.2 × 48 is 153.6. A display of 1536 is the classic sign of a missed decimal point: 32 × 48 was keyed in. A ten-second estimate catches errors that the calculator cannot.

14 KS3-MATH-NUM-0042

Which one of these is best done on a calculator rather than in your head: 50% of £386, 386 × 100 or 386 ÷ 17?

386 ÷ 17

提示Two of the three need only a halving or a shift in place value.

为什么Halving and multiplying by 100 are one-step mental jobs. Dividing by 17 has no shortcut and does not come out exactly, so a calculator, with an estimate of about 20 alongside, is the sensible tool.

15 KS3-MATH-NUM-0043

234 pupils are going on a trip in coaches that seat 52 each. A calculator gives 234 ÷ 52 = 4.5. How many coaches must be booked?

5 coaches

提示Can you book part of a coach, and can anyone be left behind?

为什么Four coaches seat only 208, leaving 26 pupils without a seat, so a fifth is needed. A calculator gives the number; you decide what it means in the situation.

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