Physics

Forces and motion, Year 11: falling and terminal velocity

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PhysicsForces and motion, Year 11: falling and terminal velocity
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
⌨ Type the answerAnswer in your head…What value does AQA give for the acceleration of an object falling freely near the Earth's surface, in m/s²? (number only)

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

9.8

HintIt is the same number as the Earth's gravitational field strength in N/kg.

The whyAny object falling freely near the Earth, with nothing but gravity acting, gains about 9.8 m/s of velocity every second. It is no accident that this matches g = 9.8 N/kg: weight = m g, and dividing that force by the mass gives the acceleration.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…A stone is dropped from rest and falls 10 m. Its acceleration is 9.8 m/s² and air resistance can be ignored. Use (final velocity)² − (initial velocity)² = 2 × acceleration × distance to find its speed just before it lands.
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

14 m/s

HintThe stone starts from rest, so one term in the equation is zero; the last step is a square root.

The whyIn symbols the equation is v² − u² = 2 a s. With u = 0, v² = 2 × 9.8 × 10 = 196, so v = √196. AQA gives this equation on the Physics equation sheet, so pupils need to apply it, not recall it.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
⌨ Type the answerAnswer in your head…A cyclist travelling at 6 m/s brakes with a uniform deceleration of 1.5 m/s² until she stops. Use v² − u² = 2 a s to find how far she travels while braking, in metres. (number only)

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

12

HintShe ends at rest, and a deceleration goes into the equation as a negative acceleration.

The whyHere v = 0, u = 6 m/s and a = −1.5 m/s². So 0² − 6² = 2 × (−1.5) × s, which gives −36 = −3 s and s = 12. The two minus signs cancel, leaving a positive distance. The equation is on the Physics equation sheet.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…The equation v² − u² = 2 a s can only be used for one kind of motion. Which?
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

Motion with uniform (constant) acceleration

HintThink about which of the four quantities must not change while the object moves.

The whyThe equation assumes the velocity changes at a steady rate over the whole distance s. Free fall with no air resistance and steady braking fit that; a car whose driver keeps changing the pressure on the pedal does not.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…A heavy steel ball and a light wooden ball are dropped together from the same height. Air resistance is small enough to ignore. Which one lands first?
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

Neither — they land together

HintThe acceleration of free fall near the Earth is one value for every object.

The whyAny object falling freely near the Earth's surface accelerates at about 9.8 m/s², whatever its mass. Gravity pulls harder on the heavy ball, but that ball also has more mass to speed up, and the two effects cancel exactly.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
↔ Asked both waysAnswer in your head…The steady velocity a falling object reaches when the resistance from the air or liquid it is falling through equals its weight
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

Terminal velocity

HintA skydiver reaches it after falling for several seconds.

The whyAt this point the resultant force on the object is zero, so by Newton's first law it stops speeding up and carries on falling at a constant velocity. It applies to anything falling through a fluid — a gas or a liquid.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…A skydiver has just stepped out of the aircraft. Why does she speed up at first?
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

Her weight is greater than the air resistance on her

HintCompare the size of the downward force with the upward one at the start.

The whyAt the start she is moving slowly, so the air resistance is small while gravity pulls her down with her full weight. The resultant force is downwards, so she accelerates. Anything dropped into a gas or a liquid starts by speeding up, because gravity is the only large force on it.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Fill the gapAnswer in your head…As a falling object speeds up, the air resistance acting on it ____.
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

increases

HintThink of how the wind feels on your face as a bike goes faster.

The whyThe faster an object moves through a fluid, the more fluid it has to push aside each second, so the resistive force grows. The weight stays the same, so the resultant force gets smaller and smaller until it reaches zero.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…A skydiver is falling at her terminal velocity. Is she still accelerating? Explain.
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

No — the resultant force on her is zero

HintUse Newton's first law on a faller whose forces balance.

The whyAt terminal velocity the upward air resistance equals her downward weight, so the forces are balanced. With no resultant force her velocity cannot change, so she falls at a constant speed in a straight line. She is still moving fast — just not getting any faster.

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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton
Answer in your head…One steel ball is dropped through air and an identical ball is dropped through thick oil. In which fluid is the terminal velocity lower, and why?
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Physics · Forces and motion, Year 11: falling and terminal velocityProfessor Newton

In the oil — its resistance is much larger, so it balances the weight at a lower speed

HintAsk how fast each ball must go before the upward force is big enough.

The whyBoth balls have the same weight to balance. Thick oil resists motion far more strongly than air does, so the resistive force reaches the size of the weight while the ball is still moving slowly. In air the ball must be going much faster before the forces balance.

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Forces and motion, Year 11: falling and terminal velocity

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