Every card in Electricity and magnetism, Year 10: power, energy and the National Grid
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- power = potential difference × ____
current
HintIt is the quantity an ammeter reads.
WhyIn symbols, P = V I, with P in watts, V in volts and I in amperes. AQA expects this equation to be recalled. It says that a device is powerful if a large amount of charge passes each second, or each coulomb transfers a lot of energy, or both.
- An electric heater takes a current of 10 A from the 230 V mains. Calculate its power in watts. (number only)
2300
HintMultiply the two readings together.
WhyP = V × I = 230 × 10. This equation must be recalled. The answer, 2.3 kW, is typical of a household heater or kettle.
- Write the equation that gives the power of a component from the current through it and its resistance.
power = current² × resistance
HintOne of the two quantities appears twice over.
WhyIn symbols, P = I² R. It comes from putting V = I R into P = V I, and AQA expects it to be recalled in its own right. It is the equation to use when the potential difference is not known.
- A current of 2 A flows through a 5 Ω resistor. Calculate the power transferred by the resistor.
20 W
HintSquare before you multiply.
WhyP = I² × R = 2² × 5 = 4 × 5. Only the current is squared. This energy heats the resistor, which is why resistors and wires warm up when they carry a current.
- A 60 W lamp runs from a 12 V supply. Calculate the current through the lamp.
5 A
HintRearrange the equation that links these three quantities so the unknown is on its own.
WhyRearranging P = V I gives I = P ÷ V = 60 ÷ 12. Checking back: 12 V × 5 A = 60 W. This rearrangement is how the correct fuse or cable for an appliance is chosen.
- A 50 Ω resistor transfers energy at a rate of 2 W. Calculate the current through it.
0.2 A
HintGet the squared quantity on its own first; the final step is a root.
WhyRearranging P = I² R gives I² = P ÷ R = 2 ÷ 50 = 0.04, and the square root of 0.04 is 0.2. Checking back: 0.2² × 50 = 0.04 × 50 = 2 W.
- energy transferred = power × ____
time
HintA kettle left on for longer costs more to run.
WhyIn symbols, E = P t, with E in joules, P in watts and t in seconds. AQA expects the equation to be recalled. The energy an appliance transfers depends on both its power rating and how long it is switched on.
- A 2 kW kettle is switched on for 3 minutes. How much energy does it transfer, in joules?
360 000 J
HintNeither number is yet in the unit the equation needs.
WhyConvert first: 2 kW = 2000 W and 3 minutes = 180 s. Then E = P × t = 2000 × 180. Working in watts and seconds is what gives an answer in joules.
- Write, in words, the equation that links the energy transferred in a circuit to the charge that flows and the potential difference.
energy transferred = charge flow × potential difference
HintA volt is a joule for every coulomb.
WhyIn symbols, E = Q V, with E in joules, Q in coulombs and V in volts. AQA expects it to be recalled. It says that work is done whenever charge flows, and that each coulomb transfers a number of joules equal to the potential difference.
- A charge of 20 C flows through a lamp that has a potential difference of 12 V across it. How much energy is transferred, in joules? (number only)
240
HintEach coulomb transfers 12 J.
WhyE = Q × V = 20 × 12. This equation must be recalled. The energy is transferred from the supply to the lamp, and from there to the surroundings as light and heating.
- A battery-powered fan is switched on. Describe the useful energy transfer that takes place.
From the chemical store of the battery to the kinetic store of the fan
HintName where the energy starts and where the useful part of it ends up.
WhyThe battery does electrical work as charge flows through the motor, and the motor turns the blades. Some energy is also dissipated, heating the motor and the air. AQA expects pupils to describe how appliances transfer energy from batteries or the mains to the kinetic energy of motors or to heating devices.
- A 3 V battery drives a current of 0.5 A through a lamp for 60 s. How much energy is transferred to the lamp?
90 J
HintFirst find how much charge has gone through; then what each coulomb delivered.
WhyCharge flow Q = I × t = 0.5 × 60 = 30 C. Energy E = Q × V = 30 × 3. The same answer comes from finding the power, P = V × I = 1.5 W, and multiplying by the 60 s.
- The system of cables and transformers that links power stations to consumers
The National Grid
HintTwo words: the first means 'belonging to the whole country', the second is a network of crossing lines.
WhyPower stations feed electrical power in, and homes, schools and factories take it out, often hundreds of kilometres away. Because everything is linked, a town is not left dark when a single station shuts down.
- A device that increases the potential difference of an alternating supply
A step-up transformer
HintIts name says which way the potential difference goes, as on a staircase.
WhyIn the National Grid these sit between the power stations and the transmission cables. Raising the potential difference lowers the current needed to carry the same power. AQA does not require knowledge of how the device is built.
- Why is electrical power sent along the National Grid's transmission cables at a very high potential difference?
For the same power the current is smaller, so less energy is wasted heating the cables
HintThe long wires have resistance; ask what makes them warm up.
WhyPower is potential difference × current, so the same power can be carried by a high potential difference and a low current. The heating in a cable depends on the current squared (P = I² R), so a small current wastes very little. That is why the Grid is an efficient way to transfer energy.
- Why does the National Grid use step-down transformers before electricity reaches homes?
To lower the potential difference to a much safer value for domestic use
HintThe cables on pylons run at hundreds of thousands of volts.
WhyThe very high potential difference that makes transmission efficient would be extremely dangerous in a house and would destroy ordinary appliances. Step-down transformers reduce it, in stages, to about 230 V for homes.
- Where in the National Grid are step-up transformers placed?
Between the power stations and the transmission cables
HintThe potential difference must be raised before the long journey begins.
WhyThe order is: power station, step-up transformer, transmission cables, step-down transformer, consumer. The potential difference is raised for the long-distance part of the journey only, and lowered again at the far end.
- The primary coil of an ideal transformer has a potential difference of 230 V across it and carries a current of 2 A. The potential difference across the secondary coil is 23 V. Calculate the current in the secondary coil.
20 A
HintIn an ideal transformer the power going in equals the power coming out.
WhyUse Vp × Ip = Vs × Is, so 230 × 2 = 23 × Is and Is = 460 ÷ 23. Stepping the potential difference down by a factor of ten steps the current up by the same factor. This equation is given on the AQA equation sheet and is Higher tier only.
1★ GCSE-PHYS-ELE-0042
2★ GCSE-PHYS-ELE-0043
3★ GCSE-PHYS-ELE-0044
4★ GCSE-PHYS-ELE-0045
5★ GCSE-PHYS-ELE-0046
6★ GCSE-PHYS-ELE-0047
7★ GCSE-PHYS-ELE-0048
8★ GCSE-PHYS-ELE-0049
9★ GCSE-PHYS-ELE-0050
10★ GCSE-PHYS-ELE-0051
11★ GCSE-PHYS-ELE-0052
12★ GCSE-PHYS-ELE-0053
13★ GCSE-PHYS-ELE-0054
14★ GCSE-PHYS-ELE-0055
15★ GCSE-PHYS-ELE-0056
16★ GCSE-PHYS-ELE-0057
17★ GCSE-PHYS-ELE-0058
18★ GCSE-PHYS-ELE-0059
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