Mathematics · Professor Pi

Every card in Geometry and measures, Year 9: Pythagoras and angle reasoning

The whole deck, in order — so you can read it through before your child ever sees it.

1 KS3-MATH-GEO-0013

The longest side of a right-angled triangle, the one opposite the right angle

The hypotenuse

HintIt is the only side that does not touch the square corner.

WhyPythagoras' theorem is built around this side: its square equals the squares on the other two sides added together. Find it before doing any arithmetic, because it decides whether you add or subtract.

2 KS3-MATH-GEO-0014

A rectangle is 5 cm wide and 12 cm long. How long is its diagonal, in cm? (number only)

13

HintThe diagonal cuts the rectangle into two triangles, each with a square corner.

WhyThe width and length meet at a right angle, so the diagonal is the hypotenuse of a triangle with shorter sides 5 and 12. Then 5² + 12² = 25 + 144 = 169, and √169 = 13.

3 KS3-MATH-GEO-0015

A triangle has sides a, b and c, where c is the longest. What must be true of the triangle for a² + b² = c² to hold?

It must be right-angled

HintThink about the one special corner the theorem depends on.

WhyThe rule only works when the two shorter sides meet at 90°, with c opposite that corner. If the angle is smaller than 90°, a² + b² comes out bigger than c²; if it is larger, a² + b² comes out smaller.

4 KS3-MATH-GEO-0016

A triangle has sides of 5 cm, 6 cm and 8 cm. Use Pythagoras' theorem to decide whether it is right-angled.

No: 5² + 6² = 61, but 8² = 64

HintSquare all three lengths, then see whether the two smaller squares make the largest.

WhyIn a right-angled triangle the two smaller squares add up to the largest exactly. Here 25 + 36 = 61, which misses 64, so no angle of this triangle is 90°.

5 KS3-MATH-GEO-0017

A right-angled triangle has a hypotenuse of 17 cm and one shorter side of 8 cm. The square of the other shorter side is ____, so that side is ____ cm long.

225; 15 cm

HintThe longest side's square is the total, so the missing square is what remains once the known one is removed.

WhyThe theorem says 8² + (missing side)² = 17², and 17² = 289 while 8² = 64, so the missing square is 289 − 64. Taking the square root at the end turns that square back into a length.

6 KS3-MATH-GEO-0018

A 10 m ladder leans against a vertical wall. Its foot is on level ground, 6 m from the base of the wall. How far up the wall does the ladder reach?

8 m

HintThe ladder itself faces the square corner where the wall meets the ground.

WhyThe wall and the ground meet at a right angle, so the ladder is the hypotenuse. The height is a shorter side: 10² − 6² = 100 − 36 = 64, and √64 = 8.

7 KS3-MATH-GEO-0019

In a right-angled triangle, the two sides that meet at the right angle are 9 cm and 12 cm. To find the third side, do you add or subtract the squares?

Add them

HintDecide first whether the unknown side is the one facing the square corner.

WhyThe sides that meet at the right angle are the two shorter sides, so the unknown is the hypotenuse: 81 + 144 = 225, giving 15 cm. You subtract only when the hypotenuse is one of the lengths you already know.

8 KS3-MATH-GEO-0020

A right-angled triangle has a hypotenuse of 15 cm. A pupil works out that one of its other sides is 17.5 cm. Without redoing the calculation, how do you know this is wrong?

No side can be longer than the hypotenuse

HintCompare the size of the answer against the 15 cm already given.

WhyThe hypotenuse faces the largest angle, so it is always the longest of the three sides. An answer bigger than it usually means the squares were added when they should have been subtracted.

9 KS3-MATH-GEO-0021

An isosceles triangle has two equal sides of 5 cm and a base of 8 cm. A straight line is drawn from the top corner to the midpoint of the base, meeting the base at right angles. How long is that line, in cm? (number only)

3

HintThe line splits the shape into two matching right-angled triangles — work out the short base of one of them first.

WhyEach half is a right-angled triangle with hypotenuse 5 and base 4, half of 8. The height is then √(5² − 4²) = √(25 − 16) = √9 = 3. Many problems hide a right-angled triangle like this inside another shape.

10 KS3-MATH-GEO-0022

Two parallel lines are crossed by a third straight line. Two angles lie between the parallel lines, on opposite sides of the crossing line, one at each crossing point. One is 65°, so the other is 65° too. What reason should be written beside this step?

Alternate angles are equal

HintPicture the letter Z drawn across the two lines.

WhyA geometric argument gives the name of the fact used, not a sketch of a letter. "Alternate angles are equal", "corresponding angles are equal" and "co-interior angles add up to 180°" are the three parallel-line reasons.

11 KS3-MATH-GEO-0023

Two angles of a triangle are 50° and 60°. The question says "Find the third angle, x. Give a reason for your answer." A pupil writes only: "x = 180 − 50 − 60 = 70°". What is missing?

The reason: angles in a triangle add up to 180°

HintThe arithmetic is fine. Ask what would tell a reader where the starting number came from.

WhyEvery claim in a geometric argument needs the fact that justifies it written beside it. Without it the reader cannot tell whether 180 came from a triangle, a straight line or a guess.

12 KS3-MATH-GEO-0024

In a parallelogram, two angles that are next to each other add up to ____°.

180

HintThey sit inside a pair of parallel sides, on one side of the line joining them — the C shape.

WhyEach pair of neighbouring corners lies between two parallel sides, so the reason to write is "co-interior angles add up to 180°". Knowing one angle of a parallelogram therefore gives you all four.

13 KS3-MATH-GEO-0025

Triangle ABC is isosceles with AB = AC, and angle BAC is 40°. Side BC is extended in a straight line beyond C to a point D. Each base angle of the triangle is ____°, so angle ACD is ____°.

70°; 110°

HintShare what is left of the triangle's total equally between B and C, then use the straight line through C.

WhyBase angles of an isosceles triangle are equal and the three angles total 180°, so each base angle is (180 − 40) ÷ 2. Angle ACD sits beside angle ACB on a straight line, so the two add up to 180°.

14 KS3-MATH-GEO-0026

Points A, B and C lie in that order on a straight line. Point D is above the line and is joined to B and to C. Angle ABD is 130° and BD = CD. How many degrees is angle BDC? (number only)

80

HintThree facts in a row: the straight line at B, the two equal sides, then the total for the triangle.

WhyAngle DBC = 180 − 130 = 50° (angles on a straight line). BD = CD, so the angles opposite those sides match and angle DCB = 50° (base angles of an isosceles triangle). Then angle BDC = 180 − 50 − 50 = 80° (angles in a triangle).

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