Every card in Geometry and measures, Year 10: pyramids, cones, spheres and sectors
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- A pyramid has a square base with sides of 6 cm and a perpendicular height of 10 cm. Using volume of a pyramid = 1/3 × base area × height, what is its volume?
120 cm³
HintWork out the area of the square first, then take the fraction named in the formula.
WhyBase area = 6 × 6 = 36 cm². Volume = 1/3 × 36 × 10 = 120 cm³. A pyramid fills exactly one third of the prism with the same base and height.
- A cone has a base radius of 3 cm, a perpendicular height of 4 cm and a slant height of 5 cm. Using volume of a cone = 1/3 × π × r² × h, what is its volume in terms of π?
12π cm³
HintThe formula's h is measured straight up the middle, not along the sloping edge.
WhyVolume = 1/3 × π × 3² × 4 = 1/3 × 36π = 12π cm³. The slant height is not used for volume; it belongs to the curved surface area. AQA gives the cone formula in the question.
- A sphere has a radius of 3 cm. Using volume of a sphere = 4/3 × π × r³, what is its volume in terms of π?
36π cm³
HintCube the radius first, then deal with the fraction.
Whyr³ = 27. Volume = 4/3 × π × 27 = 4 × 9 × π = 36π cm³. AQA gives the sphere formula in the question.
- A cone has ____ of the volume of a cylinder with the same base and the same height.
one third
HintCompare πr²h with the formula for the pointed solid.
WhyCylinder: πr²h. Cone: 1/3 × πr²h. The same fraction links a pyramid to the prism with the same base and height.
- A cone has a volume of 100π cm³ and a base radius of 5 cm. Using volume of a cone = 1/3 × π × r² × h, what is its perpendicular height in cm? (number only)
12
HintPut the known values into the formula, cancel the symbol on both sides, and solve for the missing letter.
Why100π = 1/3 × π × 25 × h. Dividing by π gives 100 = 25h ÷ 3, so 25h = 300 and h = 12 cm.
- A sphere has a radius of 5 cm. Using surface area of a sphere = 4 × π × r², what is its surface area in terms of π?
100π cm²
HintSquare the radius before multiplying by anything else.
Why4 × π × 5² = 4 × 25 × π = 100π cm². That is exactly four times the area of a circle with the same radius. AQA gives this formula in the question.
- A cone has a base radius of 5 cm and a perpendicular height of 12 cm. What is its slant height in cm? (number only)
13
HintThe radius, the perpendicular height and the sloping edge make a right-angled triangle.
WhyThe slant height l is the hypotenuse: l² = 5² + 12² = 25 + 144 = 169, so l = 13 cm. The curved surface area formula, π × r × l, needs the slant height, so this step often comes first.
- A solid cone has a base radius of 6 cm and a slant height of 10 cm. Using curved surface area = π × r × l, its curved surface has an area of ____π cm², and its total surface area, including the circular base, is ____π cm².
60; 96
HintFind the sloping part first, then remember the flat face the cone stands on.
WhyCurved surface = π × 6 × 10 = 60π cm². The base is a circle of area π × 6² = 36π cm². Total = 60π + 36π = 96π cm². AQA gives the curved surface formula in the question.
- A pyramid has a square base with sides of 10 cm. Each of its four triangular faces has a height of 12 cm, measured up the face from the middle of a base edge. What is the total surface area of the pyramid?
340 cm²
HintCount the faces: one four-sided, the rest three-sided and all alike.
WhyBase = 10 × 10 = 100 cm². Each triangular face = 1/2 × 10 × 12 = 60 cm², and there are four of them: 240 cm². Total = 100 + 240 = 340 cm².
- A solid hemisphere has a radius of 4 cm. Using surface area of a sphere = 4 × π × r², what is the total surface area of the hemisphere in terms of π?
48π cm²
HintHalf of the ball's skin is only part of it: cutting a ball in two exposes a new flat face.
WhyCurved part = half of 4 × π × 4² = 32π cm². The flat face is a circle of area π × 4² = 16π cm². Total = 32π + 16π = 48π cm².
- What fraction of a full circle is a sector with an angle of 45° at the centre? Give a fraction in its simplest form.
1/8
HintCompare the angle with a complete turn.
WhyA full turn is 360°, so the sector is 45/360 = 1/8 of the circle. The same fraction gives the sector's share of both the area and the circumference.
- A sector has a radius of 9 cm and an angle of 80° at the centre. What is the length of its arc, in terms of π?
4π cm
HintFind the whole distance round the circle, then take the share that the angle gives.
WhyCircumference = 2 × π × 9 = 18π cm. The sector is 80/360 = 2/9 of the circle, so the arc is 2/9 × 18π = 4π cm.
- A sector has a radius of 6 cm and an angle of 60° at the centre. What is its area, in terms of π?
6π cm²
HintSixty degrees is a simple fraction of a full turn: apply it to the area of the whole circle.
WhyArea of the circle = π × 6² = 36π cm². The sector is 60/360 = 1/6 of it: 36π ÷ 6 = 6π cm².
- A sector of a circle of radius 10 cm has an area of 25π cm². What is the angle of the sector, in degrees? (number only)
90
HintCompare the sector's area with the area of the complete circle to see what share it is.
WhyThe full circle has area π × 10² = 100π cm². The sector is 25π ÷ 100π = 1/4 of it, and 1/4 of 360° is 90°.
- A sector has a radius of 10 cm and an angle of 90° at the centre. Using π = 3.14, its arc is ____ cm long and its perimeter is ____ cm.
15.7; 35.7
HintWalk all the way round the edge of the slice: one curved part and two straight parts.
WhyArc = 90/360 × 2 × 3.14 × 10 = 15.7 cm. The perimeter also includes the two radii: 15.7 + 10 + 10 = 35.7 cm.
1★ GCSE-MATH-GEO-0045
2★ GCSE-MATH-GEO-0046
3★ GCSE-MATH-GEO-0047
4★ GCSE-MATH-GEO-0048
5★ GCSE-MATH-GEO-0049
6★ GCSE-MATH-GEO-0050
7★ GCSE-MATH-GEO-0051
8★ GCSE-MATH-GEO-0052
9★ GCSE-MATH-GEO-0053
10★ GCSE-MATH-GEO-0054
11★ GCSE-MATH-GEO-0055
12★ GCSE-MATH-GEO-0056
13★ GCSE-MATH-GEO-0057
14★ GCSE-MATH-GEO-0058
15★ GCSE-MATH-GEO-0059
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