Every card in Algebra, Year 8: brackets, inequalities, lines and indices
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← Back to Algebra, Year 8: brackets, inequalities, lines and indices
- Solve 3(x + 2) = 18.
x = 4
HintYou could divide both sides by 3 first.
WhyDividing by 3 gives x + 2 = 6, so x = 4. Expanding gives 3x + 6 = 18 and the same answer. Check: 3 × (4 + 2) = 18.
- Solve 5(x − 1) = 20.
x = 5
HintWhat must the bracket be worth?
WhyFive lots of the bracket make 20, so the bracket is 4. Then x − 1 = 4 gives x = 5. Check: 5 × (5 − 1) = 20.
- Solve 2(3x + 1) = 20.
x = 3
HintHalve both sides, then treat it as a two-step equation.
WhyDividing by 2 gives 3x + 1 = 10, so 3x = 9 and x = 3. Check: 2 × (9 + 1) = 20.
- Solve 4(x + 3) = 10.
x = −0.5
HintDividing first gives a decimal; expanding first works just as well.
WhyExpanding: 4x + 12 = 10, so 4x = −2 and x = −0.5. Dividing first: x + 3 = 2.5. When the division is awkward, expanding is often the easier route.
- On a number line, what kind of circle shows that the end value is NOT included, as in x > 2?
An open (hollow) circle
HintIt is the opposite of the dot used when the end value counts.
WhyAn unfilled circle is used for < and >, where the end value is left out. A filled circle is used for ≤ and ≥, where it counts.
- Which integers satisfy −1 ≤ x < 3?
−1, 0, 1, 2
HintCheck each end: one is included and one is not.
Whyx can equal −1, because the sign is ≤, but it must be less than 3, so 3 is left out. Zero is an integer and must not be forgotten.
- A number line shows a filled circle at 4 with an arrow pointing left. Write the inequality.
x ≤ 4
HintFilled means the end value counts.
WhyThe arrow covers every number below 4, and the filled circle says that 4 itself is included, so the sign is 'less than or equal to'.
- A number line shows an open circle at −2 and a filled circle at 5, joined by a line. Write the inequality.
−2 < x ≤ 5
HintWrite x in the middle and decide each sign separately.
WhyThe open circle at −2 means x is greater than −2 but not equal to it. The filled circle at 5 means x can be 5.
- For y = 2x + 1, what is y when x = −2?
−3
HintTwice a negative number is negative; then add one.
Why2 × (−2) = −4, and −4 + 1 = −3. Tables of values for straight lines should always include some negative x-values.
- For y = 3x − 2, complete the table of values for x = 0, 1, 2.
y = −2, 1, 4
HintEach y is 3 more than the one before.
Why3 × 0 − 2 = −2, 3 × 1 − 2 = 1 and 3 × 2 − 2 = 4. Equal steps in x give equal steps in y, which is why the points lie on a straight line.
- You plot five points from a table of values for y = 2x + 1. Four lie on a straight line and one does not. What should you do?
Re-check the calculation for that point
HintA linear rule cannot make a kink.
WhyEvery point of y = 2x + 1 lies on one straight line, so a stray point signals an arithmetic slip, often with a negative number.
- What is the equation of the vertical line through (−2, 0), (−2, 3) and (−2, −5)?
x = −2
HintAsk which coordinate never changes.
WhyEvery point on the line has an x-coordinate of −2, whatever its height. The equation states the one thing that is always true.
- Is the line y = 2 horizontal or vertical?
Horizontal
HintEvery point on it is the same height above the x-axis.
WhyAll its points have a y-coordinate of 2, such as (0, 2) and (5, 2), so the line runs level, two units up.
- What is the equation of the x-axis?
y = 0
HintThink about what all its points have in common.
WhyEvery point on the x-axis has a height of nothing: (1, 0), (2, 0), (−4, 0). In the same way, the y-axis is x = 0.
- Where do the lines x = 4 and y = −1 cross?
(4, −1)
HintOne line fixes the across number; the other fixes the up-down number.
WhyThe crossing point lies on both lines, so its x-coordinate is 4 and its y-coordinate is −1.
- Simplify a³ × a⁴.
a⁷
HintWrite each power out as a string of a's and count them.
Whya³ is a × a × a and a⁴ is a × a × a × a. Together that is seven a's multiplied, so the indices are added.
- Simplify a⁸ ÷ a².
a⁶
HintCancel two a's from the top.
WhyEight a's on top and two underneath: two pairs cancel, leaving six. When dividing powers of one letter, subtract the indices.
- Simplify 2a² × 3a³.
6a⁵
HintMultiply the numbers; deal with the letters separately.
Why2 × 3 = 6 and a² × a³ = a⁵. The numbers are multiplied in the ordinary way; only the indices are added.
- Can a³ × b² be simplified by adding the indices?
No — the bases are different
HintWrite both out in full and see what you get.
Whya × a × a × b × b cannot be written as a single power, because the letters differ. It stays as a³b².
1★ KS3-MATH-ALG-0068
2★ KS3-MATH-ALG-0069
3★ KS3-MATH-ALG-0070
4★ KS3-MATH-ALG-0071
5★ KS3-MATH-ALG-0072
6★ KS3-MATH-ALG-0073
7★ KS3-MATH-ALG-0074
8★ KS3-MATH-ALG-0075
9★ KS3-MATH-ALG-0076
10★ KS3-MATH-ALG-0077
11★ KS3-MATH-ALG-0078
12★ KS3-MATH-ALG-0079
13★ KS3-MATH-ALG-0080
14★ KS3-MATH-ALG-0081
15★ KS3-MATH-ALG-0082
16★ KS3-MATH-ALG-0083
17★ KS3-MATH-ALG-0084
18★ KS3-MATH-ALG-0085
19★ KS3-MATH-ALG-0086
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